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FleetCode

113. Path Sum II

Medium62.6% acceptance10 companies

Given the root of a binary tree and an integer targetSum, return all root-to-leaf paths where the sum of the node values in the path equals targetSum. Each path should be returned as a list of the node values, not node references.

A root-to-leaf path is a path starting from the root and ending at any leaf node. A leaf is a node with no children.

Example 1:

Input: root = [5,4,8,11,null,13,4,7,2,null,null,5,1], targetSum = 22
Output: [[5,4,11,2],[5,8,4,5]]
Explanation: There are two paths whose sum equals targetSum:
5 + 4 + 11 + 2 = 22
5 + 8 + 4 + 5 = 22

Example 2:

Input: root = [1,2,3], targetSum = 5
Output: []

Example 3:

Input: root = [1,2], targetSum = 0
Output: []

Constraints:

  • The number of nodes in the tree is in the range [0, 5000].
  • -1000 <= Node.val <= 1000
  • -1000 <= targetSum <= 1000
9:13
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1# Definition for a binary tree node.
2# class TreeNode:
3# def __init__(self, val=0, left=None, right=None):
4# self.val = val
5# self.left = left
6# self.right = right
7class Solution:
8 def pathSum(self, root: Optional[TreeNode], targetSum: int) -> List[List[int]]:
9
Starter codePython 3Spaces: 4
Examples
Input
[5,4,8,11,null,13,4,7,2,null,null,5,1]
22
Input
[1,2,3]
5
Input
[1,2]
0
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