Partitioning Into Minimum Number Of Deci-Binary Numbers - Solution & Explanation

The key to solving this problem is understanding the relationship between the digits of the number and the deci-binary numbers. The minimum number of deci-binary numbers needed is dictated by the maximum digit in the string representation of the number. This is because to construct the number using deci-binary numbers (which only contain 0 and 1), at least one of these numbers must have a '1' in each digit position where the given number is non-zero. Each deci-binary number can only add 1 to each digit position.

In this C implementation, we iterate through the string of the number, keeping track of the maximum digit found. Since deci-binary numbers can only increment each position by 1, the maximum digit will determine the minimum number of such numbers required.

Instead of iterating through the string directly, an alternate way to solve the problem can be to map the string into an array of numbers first, then find the maximum in that array. However, this adds overhead without practical advantage, since the core of the solution relies on identifying the maximum digit in the string.

While this approach doesn't effectively differ in the outcome or complexity, it demonstrates the same maximum digit principle, emphasizing direct character handling in the number string.