Partitioning Into Minimum Number Of Deci-Binary Numbers Python/Java solution

The implementation is straightforward in Python, Java, C++, or JavaScript. Iterate through each character of the string, convert it to a digit, and update the maximum value seen so far. Return that maximum digit as the answer. The runtime remains O(n) across all languages.

What is the best approach for Partitioning Into Minimum Number Of Deci-Binary Numbers?

The optimal approach is a greedy scan that finds the maximum digit in the string. Since each deci-binary number can contribute at most 1 to a digit position, a digit value d requires at least d numbers. Therefore the minimum count equals the largest digit in the string. This solution runs in O(n) time with O(1) space.

Is Partitioning Into Minimum Number Of Deci-Binary Numbers asked at Google/Amazon/Meta?

This problem reflects the type of greedy reasoning frequently asked in interviews at companies like Google, Amazon, and Meta. While the exact problem may not always appear, the concept of reducing a problem to a key invariant or maximum constraint is common in coding interviews.

What data structure is used in Partitioning Into Minimum Number Of Deci-Binary Numbers?

The problem mainly uses simple string traversal and integer comparison. No advanced data structures are required. Some implementations convert the string into an integer array, but the optimal solution only tracks the maximum digit during iteration.

What is the time complexity of Partitioning Into Minimum Number Of Deci-Binary Numbers?

The optimal algorithm runs in O(n) time where n is the length of the numeric string. You only need a single pass through the digits to track the maximum digit. Space complexity is O(1) because only a few variables are used.

Description Hints 3 Solution Video 15:08

1689. Partitioning Into Minimum Number Of Deci-Binary Numbers

Q: Is Partitioning Into Minimum Number Of Deci-Binary Numbers easy or hard?

The problem is rated Medium on LeetCode but is considered relatively straightforward once the greedy insight is discovered. Many candidates initially try constructing deci-binary numbers, but recognizing that the maximum digit determines the answer simplifies the solution to a single pass.

Q: How to solve Partitioning Into Minimum Number Of Deci-Binary Numbers in O(n)?

Iterate through the string and compute the maximum digit encountered. Each deci-binary number contributes at most one to a digit position, so the largest digit determines how many numbers are required. This single scan approach solves the problem in linear O(n) time and constant space.

Medium90.5% acceptance4 companies

A decimal number is called deci-binary if each of its digits is either 0 or 1 without any leading zeros. For example, 101 and 1100 are deci-binary, while 112 and 3001 are not.

Given a string n that represents a positive decimal integer, return the minimum number of positive deci-binary numbers needed so that they sum up to n.

Example 1:

Input: n = "32"
Output: 3
Explanation: 10 + 11 + 11 = 32

Example 2:

Input: n = "82734"
Output: 8

Example 3:

Input: n = "27346209830709182346"
Output: 9

Constraints:

1 <= n.length <= 10⁵
n consists of only digits.
n does not contain any leading zeros and represents a positive integer.

Asked at 4 companies

Nutanix Zoho

Google Amazon

Topics

Greedy String

Hints open one at a time

Hint 1

Think about if the input was only one digit. Then you need to add up as many ones as the value of this digit.

Hint 2

If the input has multiple digits, then you can solve for each digit independently, and merge the answers to form numbers that add up to that input.

Hint 3

Thus the answer is equal to the max digit.

15:08

Still stuck?Read 3 approaches, or watch a walkthrough.

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1class Solution:
2    def minPartitions(self, n: str) -> int:
3        

Starter codePython 3Spaces: 4

Examples

Case 1Case 2Case 3

Input

"32"

Input

"82734"

Input

"27346209830709182346"

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