Flatten 2D Vector solution and explanation

class Vector2D:
    def __init__(self, vec: List[List[int]]):
        self.i = 0
        self.j = 0
        self.vec = vec

    def next(self) -> int:
        self.forward()
        ans = self.vec[self.i][self.j]
        self.j += 1
        return ans

    def hasNext(self) -> bool:
        self.forward()
        return self.i < len(self.vec)

    def forward(self):
        while self.i < len(self.vec) and self.j >= len(self.vec[self.i]):
            self.i += 1
            self.j = 0


# Your Vector2D object will be instantiated and called as such:
# obj = Vector2D(vec)
# param_1 = obj.next()
# param_2 = obj.hasNext()

class Vector2D {
    private int i;
    private int j;
    private int[][] vec;

    public Vector2D(int[][] vec) {
        this.vec = vec;
    }

    public int next() {
        forward();
        return vec[i][j++];
    }

    public boolean hasNext() {
        forward();
        return i < vec.length;
    }

    private void forward() {
        while (i < vec.length && j >= vec[i].length) {
            ++i;
            j = 0;
        }
    }
}

/**
 * Your Vector2D object will be instantiated and called as such:
 * Vector2D obj = new Vector2D(vec);
 * int param_1 = obj.next();
 * boolean param_2 = obj.hasNext();
 */

class Vector2D {
public:
    Vector2D(vector<vector<int>>& vec) {
        this->vec = move(vec);
    }

    int next() {
        forward();
        return vec[i][j++];
    }

    bool hasNext() {
        forward();
        return i < vec.size();
    }

private:
    int i = 0;
    int j = 0;
    vector<vector<int>> vec;

    void forward() {
        while (i < vec.size() && j >= vec[i].size()) {
            ++i;
            j = 0;
        }
    }
};

/**
 * Your Vector2D object will be instantiated and called as such:
 * Vector2D* obj = new Vector2D(vec);
 * int param_1 = obj->next();
 * bool param_2 = obj->hasNext();
 */

class Vector2D {
    i: number;
    j: number;
    vec: number[][];

    constructor(vec: number[][]) {
        this.i = 0;
        this.j = 0;
        this.vec = vec;
    }

    next(): number {
        this.forward();
        return this.vec[this.i][this.j++];
    }

    hasNext(): boolean {
        this.forward();
        return this.i < this.vec.length;
    }

    forward(): void {
        while (this.i < this.vec.length && this.j >= this.vec[this.i].length) {
            ++this.i;
            this.j = 0;
        }
    }
}

/**
 * Your Vector2D object will be instantiated and called as such:
 * var obj = new Vector2D(vec)
 * var param_1 = obj.next()
 * var param_2 = obj.hasNext()
 */

type Vector2D struct {
	i, j int
	vec  [][]int
}

func Constructor(vec [][]int) Vector2D {
	return Vector2D{vec: vec}
}

func (this *Vector2D) Next() int {
	this.forward()
	ans := this.vec[this.i][this.j]
	this.j++
	return ans
}

func (this *Vector2D) HasNext() bool {
	this.forward()
	return this.i < len(this.vec)
}

func (this *Vector2D) forward() {
	for this.i < len(this.vec) && this.j >= len(this.vec[this.i]) {
		this.i++
		this.j = 0
	}
}

/**
 * Your Vector2D object will be instantiated and called as such:
 * obj := Constructor(vec);
 * param_1 := obj.Next();
 * param_2 := obj.HasNext();
 */