Customer Placing the Largest Number of Orders solution and explanation

import sqlite3

def get_largest_order_customer():
    connection = sqlite3.connect(':memory:')
    cursor = connection.cursor()
    # Assumed table creation and data insertion here.
    query = '''
    SELECT customer_number
    FROM Orders
    GROUP BY customer_number
    ORDER BY COUNT(order_number) DESC
    LIMIT 1;
    '''
    cursor.execute(query)
    result = cursor.fetchone()
    if result:
        print(f"Customer Number: {result[0]}")
    connection.close()

get_largest_order_customer()

import java.sql.Connection;
import java.sql.DriverManager;
import java.sql.ResultSet;
import java.sql.Statement;

public class LargestOrderCustomer {
    public static void main(String[] args) {
        try {
            Connection connection = DriverManager.getConnection("jdbc:sqlite::memory:");
            Statement stmt = connection.createStatement();
            // Assume table creation and data population here.
            String sql = "SELECT customer_number FROM Orders GROUP BY customer_number ORDER BY COUNT(order_number) DESC LIMIT 1;";
            ResultSet rs = stmt.executeQuery(sql);
            if (rs.next()) {
                System.out.println("Customer Number: " + rs.getInt(1));
            }
            rs.close();
            stmt.close();
            connection.close();
        } catch (Exception e) {
            e.printStackTrace();
        }
    }
}

#include <iostream>
#include <sqlite3.h>

void findLargestOrderCustomer(sqlite3* db) {
    sqlite3_stmt* stmt;
    const char* sql = "SELECT customer_number FROM Orders GROUP BY customer_number ORDER BY COUNT(order_number) DESC LIMIT 1;";

    if (sqlite3_prepare_v2(db, sql, -1, &stmt, 0) == SQLITE_OK) {
        if (sqlite3_step(stmt) == SQLITE_ROW) {
            std::cout << "Customer Number: " << sqlite3_column_int(stmt, 0) << std::endl;
        }
        sqlite3_finalize(stmt);
    }
}

int main() {
    sqlite3* db;
    sqlite3_open(":memory:", &db);
    // Assume table creation and data population.
    findLargestOrderCustomer(db);
    sqlite3_close(db);
    return 0;
}

const sqlite3 = require('sqlite3').verbose();

let db = new sqlite3.Database(':memory:');

// Assuming that database and Orders table are already set up
let sql = `SELECT customer_number FROM Orders GROUP BY customer_number ORDER BY COUNT(order_number) DESC LIMIT 1;`;

db.get(sql, [], (err, row) => {
  if (err) {
    throw err;
  }
  console.log(`Customer Number: ${row.customer_number}`);
});

db.close();

#include <stdio.h>
#include <stdlib.h>
#include <sqlite3.h>

/* Function to get the customer with the largest number of orders */
void getLargestOrderCustomer(sqlite3 *db) {
    sqlite3_stmt *stmt;
    const char *sql = "SELECT customer_number FROM Orders GROUP BY customer_number ORDER BY COUNT(order_number) DESC LIMIT 1;";
    
    if (sqlite3_prepare_v2(db, sql, -1, &stmt, 0) == SQLITE_OK) {
        if (sqlite3_step(stmt) == SQLITE_ROW) {
            int customer_number = sqlite3_column_int(stmt, 0);
            printf("Customer Number: %d\n", customer_number);
        }
        sqlite3_finalize(stmt);
    }
}

int main() {
    sqlite3 *db;
    sqlite3_open(":memory:", &db);
    // Assume table creation and data insertion is done here.
    getLargestOrderCustomer(db);
    sqlite3_close(db);
    return 0;
}

using System;
using System.Data.SQLite;

class Program {
    static void Main() {
        using (var connection = new SQLiteConnection("Data Source=:memory:")) {
            connection.Open();
            using (var command = new SQLiteCommand(connection)) {
                // Assumes table and data exist in SQLite.
                command.CommandText = @"
                SELECT customer_number
                FROM Orders
                GROUP BY customer_number
                ORDER BY COUNT(order_number) DESC
                LIMIT 1;";
                using (var reader = command.ExecuteReader()) {
                    if (reader.Read()) {
                        Console.WriteLine("Customer Number: " + reader.GetInt32(0));
                    }
                }
            }
        }
    }
}

def find_customer_with_most_orders(orders):
    order_count = {}
    # Count orders per customer
    for order in orders:
        customer = order['customer_number']
        if customer in order_count:
            order_count[customer] += 1
        else:
            order_count[customer] = 1
    
    # Find the customer with the maximum orders
    max_orders = -1
    max_customer = -1
    for customer, count in order_count.items():
        if count > max_orders:
            max_orders = count
            max_customer = customer
    
    return max_customer

orders = [{'order_number': 1, 'customer_number': 1}, {'order_number': 2, 'customer_number': 2}, {'order_number': 3, 'customer_number': 3}, {'order_number': 4, 'customer_number': 3}]

print(find_customer_with_most_orders(orders))

# Write your MySQL query statement below
SELECT
    customer_number
FROM orders
GROUP BY customer_number
ORDER BY COUNT(1) DESC
LIMIT 1;

/* Write your T-SQL query statement below */
SELECT TOP 1
    customer_number
FROM
    orders
GROUP BY customer_number
ORDER BY COUNT(customer_number) DESC;