Combine Two Tables solution and explanation

SELECT p.firstName, p.lastName, A.city, A.state FROM Person p LEFT JOIN Address A ON p.personId = A.personId;

SELECT
    p.firstName, 
    p.lastName, 
    (SELECT city FROM Address WHERE personId = p.personId) AS city,
    (SELECT state FROM Address WHERE personId = p.personId) AS state
FROM Person p;

def solve(arr):
    arr.sort()
    # Logic based on sorted array
    print("Sorted Array:", ' '.join(map(str, arr)))

arr = [3, 1, 4, 1, 5]
solve(arr)

import java.util.Arrays;

public class Solution {
    public static void solve(int[] arr) {
        Arrays.sort(arr);
        // Apply logic on sorted array
        System.out.print("Sorted Array: ");
        for (int num : arr) System.out.print(num + " ");
    }

    public static void main(String[] args) {
        int[] arr = {3, 1, 4, 1, 5};
        solve(arr);
    }
}

#include <iostream>
#include <algorithm>
#include <vector>

void solve(std::vector<int>& vec) {
    std::sort(vec.begin(), vec.end());
    // Perform operations on sorted vector
    std::cout << "Sorted Vector: ";
    for (int num : vec) std::cout << num << " ";
    std::cout << std::endl;
}

int main() {
    std::vector<int> vec = {3, 1, 4, 1, 5};
    solve(vec);
    return 0;
}

function solve(arr) {
    arr.sort((a, b) => a - b);
    // Perform operations on sorted array
    console.log("Sorted Array:", arr.join(' '));
}

let arr = [3, 1, 4, 1, 5];
solve(arr);

#include <stdio.h>
#include <stdlib.h>

int compare(const void *a, const void *b) {
    return (*(int*)a - *(int*)b);
}

void solve(int arr[], int n) {
    qsort(arr, n, sizeof(int), compare);
    // Assume this finds the result based on sorted array
    printf("Sorted Array: ");
    for(int i = 0; i < n; i++) printf("%d ", arr[i]);
}

int main() {
    int arr[] = {3, 1, 4, 1, 5};
    int n = sizeof(arr) / sizeof(arr[0]);
    solve(arr, n);
    return 0;
}

using System;

class Solution {
    public static void Solve(int[] arr) {
        Array.Sort(arr);
        // Use sorted array for further computation
        Console.WriteLine("Sorted Array: {0}", string.Join(" ", arr));
    }

    static void Main() {
        int[] arr = {3, 1, 4, 1, 5};
        Solve(arr);
    }
}

def solve(arr):
    hashmap = {}
    for num in arr:
        if num in hashmap:
            hashmap[num] += 1
        else:
            hashmap[num] = 1
    # Check presence as example
    if 4 in hashmap:
        print("4 found!")
    else:
        print("4 not found!")

arr = [3, 1, 4, 1, 5]
solve(arr)

import java.util.HashMap;

public class Solution {
    public static void solve(int[] arr) {
        HashMap<Integer, Integer> map = new HashMap<Integer, Integer>();
        for (int num : arr) {
            map.put(num, map.getOrDefault(num, 0) + 1);
        }
        // Demonstrate finding an element
        if (map.containsKey(4))
            System.out.println("4 found!");
        else
            System.out.println("4 not found!");
    }

    public static void main(String[] args) {
        int[] arr = {3, 1, 4, 1, 5};
        solve(arr);
    }
}

#include <iostream>
#include <unordered_map>
#include <vector>

void solve(const std::vector<int>& vec) {
    std::unordered_map<int, int> map;
    for (int num : vec) {
        map[num]++;
    }
    // Example to check presence
    if (map.find(4) != map.end())
        std::cout << "4 found!" << std::endl;
    else
        std::cout << "4 not found!" << std::endl;
}

int main() {
    std::vector<int> vec = {3, 1, 4, 1, 5};
    solve(vec);
    return 0;
}

function solve(arr) {
    let map = new Map();
    for (let num of arr) {
        map.set(num, (map.get(num) || 0) + 1);
    }
    // Check if a number is present
    if (map.has(4)) {
        console.log("4 found!");
    } else {
        console.log("4 not found!");
    }
}

let arr = [3, 1, 4, 1, 5];
solve(arr);

#include <stdio.h>
#include <stdlib.h>
#include <stdbool.h>

#define TABLE_SIZE 100

typedef struct Item {
    int key;
    int value;
} Item;

typedef struct HashTable {
    Item* table[TABLE_SIZE];
} HashTable;

unsigned hash(int key) { return key % TABLE_SIZE; }

HashTable* createTable() {
    HashTable* ht = malloc(sizeof(HashTable));
    for(int i = 0; i < TABLE_SIZE; i++)
        ht->table[i] = NULL;
    return ht;
}

void insert(HashTable* ht, int key, int value) {
    unsigned idx = hash(key);
    while (ht->table[idx] != NULL && ht->table[idx]->key != key) {
        idx = (idx + 1) % TABLE_SIZE;
    }
    if (ht->table[idx] == NULL)
        ht->table[idx] = malloc(sizeof(Item));
    ht->table[idx]->key = key;
    ht->table[idx]->value = value;
}

bool search(HashTable* ht, int key) {
    unsigned idx = hash(key);
    while (ht->table[idx] != NULL && ht->table[idx]->key != key) {
        idx = (idx + 1) % TABLE_SIZE;
    }
    return ht->table[idx] != NULL && ht->table[idx]->key == key;
}

void solve(int arr[], int n) {
    HashTable* ht = createTable();
    for (int i = 0; i < n; i++) {
        insert(ht, arr[i], 1);
    }
    // Example purpose, search for a value
    printf(search(ht, 4) ? "4 found!\n" : "4 not found!\n");
}

int main() {
    int arr[] = {3, 1, 4, 1, 5};
    int n = sizeof(arr) / sizeof(arr[0]);
    solve(arr, n);
    return 0;
}

using System;
using System.Collections.Generic;

class Solution {
    public static void Solve(int[] arr) {
        Dictionary<int, int> map = new Dictionary<int, int>();
        foreach (int num in arr) {
            if (map.ContainsKey(num))
                map[num]++;
            else
                map[num] = 1;
        }
        if (map.ContainsKey(4))
            Console.WriteLine("4 found!");
        else
            Console.WriteLine("4 not found!");
    }

    static void Main() {
        int[] arr = {3, 1, 4, 1, 5};
        Solve(arr);
    }
}