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FleetCode

700. Search in a Binary Search Tree

Easy83.1% acceptance5 companies

You are given the root of a binary search tree (BST) and an integer val.

Find the node in the BST that the node's value equals val and return the subtree rooted with that node. If such a node does not exist, return null.

Example 1:

Input: root = [4,2,7,1,3], val = 2
Output: [2,1,3]

Example 2:

Input: root = [4,2,7,1,3], val = 5
Output: []

Constraints:

  • The number of nodes in the tree is in the range [1, 5000].
  • 1 <= Node.val <= 107
  • root is a binary search tree.
  • 1 <= val <= 107
6:15
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Open solution
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1# Definition for a binary tree node.
2# class TreeNode:
3# def __init__(self, val=0, left=None, right=None):
4# self.val = val
5# self.left = left
6# self.right = right
7class Solution:
8 def searchBST(self, root: Optional[TreeNode], val: int) -> Optional[TreeNode]:
9
Starter codePython 3Spaces: 4
Examples
Input
[4,2,7,1,3]
2
Input
[4,2,7,1,3]
5
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