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637. Average of Levels in Binary Tree

Easy74.8% acceptance4 companies
Given the root of a binary tree, return the average value of the nodes on each level in the form of an array. Answers within 10-5 of the actual answer will be accepted.

Example 1:

Input: root = [3,9,20,null,null,15,7]
Output: [3.00000,14.50000,11.00000]
Explanation: The average value of nodes on level 0 is 3, on level 1 is 14.5, and on level 2 is 11.
Hence return [3, 14.5, 11].

Example 2:

Input: root = [3,9,20,15,7]
Output: [3.00000,14.50000,11.00000]

Constraints:

  • The number of nodes in the tree is in the range [1, 104].
  • -231 <= Node.val <= 231 - 1

Asked at 4 companies

6:25
Still stuck?Read 4 approaches, or watch a walkthrough.
Open solution
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1# Definition for a binary tree node.
2# class TreeNode:
3# def __init__(self, val=0, left=None, right=None):
4# self.val = val
5# self.left = left
6# self.right = right
7class Solution:
8 def averageOfLevels(self, root: Optional[TreeNode]) -> List[float]:
9
Starter codePython 3Spaces: 4
Examples
Input
[3,9,20,null,null,15,7]
Input
[3,9,20,15,7]
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