Given an integer array nums and an integer k, return the kth largest element in the array.
Note that it is the kth largest element in the sorted order, not the kth distinct element.
Can you solve it without sorting?
Example 1:
Input: nums = [3,2,1,5,6,4], k = 2 Output: 5
Example 2:
Input: nums = [3,2,3,1,2,4,5,5,6], k = 4 Output: 4
Constraints:
1 <= k <= nums.length <= 105-104 <= nums[i] <= 104The goal of #215 Kth Largest Element in an Array is to find the element that appears in the kth position when the array is ordered from largest to smallest. A straightforward idea is to sort the array and directly access the element at index n - k. While simple, sorting costs O(n log n) time.
A more efficient interview-friendly approach uses a min-heap (priority queue) of size k. By keeping only the largest k elements in the heap, the root always represents the kth largest value. This reduces the time complexity to O(n log k) with O(k) space.
For optimal performance, many candidates use the Quickselect algorithm, a divide-and-conquer technique related to quicksort. It partitions the array around a pivot and recursively focuses only on the relevant side, achieving an average time complexity of O(n) and constant extra space.
| Approach | Time Complexity | Space Complexity |
|---|---|---|
| Sorting | O(n log n) | O(1) or O(n) depending on sort |
| Min Heap (size k) | O(n log k) | O(k) |
| Quickselect | Average: O(n), Worst: O(n^2) | O(1) |
NeetCode
By using a Min-Heap, we can efficiently keep track of the k largest elements. Maintain a heap of size k, and for each element in the array, decide whether to add it to the heap. If you add an element to the heap when it is full, remove the minimum element to maintain the size of the heap as k. At the end, the root of the heap will be the kth largest element.
Time Complexity: O(n log n), where n is the size of the array, because of the sorting operation.
Space Complexity: O(1), as we are modifying the input array in-place.
1#include <stdio.h>
2#include <stdlib.h>
3
4int cmpfunc (const void * a, const void * b) {
We first define a comparison function cmpfunc that is used by the C library function qsort to sort the array. After sorting, the kth largest element is located at index numsSize - k.
Quickselect is an efficient selection algorithm to find the kth smallest element in an unordered list. The algorithm is related to the quicksort sorting algorithm. It works by partitioning the data, similar to the partitioning step of quicksort, and is based on the idea of reducing the problem size through partitioning.
Average-case Time Complexity: O(n), but worst-case O(n²).
Space Complexity: O(1) for iterative solution, O(log n) for recursive calls due to stack depth.
1using System;
2
class KthLargestElement {
private static int Partition(int[] nums, int left, int right, int pivotIndex) {
int pivotValue = nums[pivotIndex];
Swap(ref nums[pivotIndex], ref nums[right]);
int newPivotIndex = left;
for (int i = left; i < right; i++) {
if (nums[i] > pivotValue) {
Swap(ref nums[newPivotIndex++], ref nums[i]);
}
}
Swap(ref nums[newPivotIndex], ref nums[right]);
return newPivotIndex;
}
private static void Swap(ref int a, ref int b) {
int temp = a;
a = b;
b = temp;
}
private static int QuickSelect(int[] nums, int left, int right, int k) {
if (left == right) return nums[left];
Random rand = new Random();
int pivotIndex = rand.Next(left, right + 1);
pivotIndex = Partition(nums, left, right, pivotIndex);
if (pivotIndex == k) return nums[k];
else if (pivotIndex < k) return QuickSelect(nums, pivotIndex + 1, right, k);
else return QuickSelect(nums, left, pivotIndex - 1, k);
}
public static int FindKthLargest(int[] nums, int k) {
return QuickSelect(nums, 0, nums.Length - 1, k - 1);
}
static void Main() {
int[] nums = {3,2,1,5,6,4};
int k = 2;
Console.WriteLine(FindKthLargest(nums, k));
}
}Watch expert explanations and walkthroughs
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Quickselect only processes the part of the array that may contain the kth largest element instead of sorting the entire array. This reduces the average time complexity from O(n log n) to O(n).
Yes, this problem is frequently asked in FAANG and other top tech company interviews. It tests knowledge of heaps, partitioning techniques, and algorithm optimization strategies like Quickselect.
A min-heap (priority queue) of size k is commonly used. By maintaining only the top k largest elements, the root of the heap always represents the kth largest value in the array.
The optimal approach is typically Quickselect, which is based on the partition idea from quicksort. It narrows the search space to only the relevant side of the array and achieves O(n) average time complexity, making it very efficient for large inputs.
The explained C# solution employs recursive logic through a randomized Quickselect setup aiming at secure partitioning against degenerative pivot dictation. Messaged swaps ensure relative positions provide shrink search domains between elimination.