Watch 10 video solutions for Reformat Department Table, a easy level problem involving Database. This walkthrough by Frederik Müller has 7,012 views views. Want to try solving it yourself? Practice on FleetCode or read the detailed text solution.
Table: Department
+-------------+---------+ | Column Name | Type | +-------------+---------+ | id | int | | revenue | int | | month | varchar | +-------------+---------+ In SQL,(id, month) is the primary key of this table. The table has information about the revenue of each department per month. The month has values in ["Jan","Feb","Mar","Apr","May","Jun","Jul","Aug","Sep","Oct","Nov","Dec"].
Reformat the table such that there is a department id column and a revenue column for each month.
Return the result table in any order.
The result format is in the following example.
Example 1:
Input: Department table: +------+---------+-------+ | id | revenue | month | +------+---------+-------+ | 1 | 8000 | Jan | | 2 | 9000 | Jan | | 3 | 10000 | Feb | | 1 | 7000 | Feb | | 1 | 6000 | Mar | +------+---------+-------+ Output: +------+-------------+-------------+-------------+-----+-------------+ | id | Jan_Revenue | Feb_Revenue | Mar_Revenue | ... | Dec_Revenue | +------+-------------+-------------+-------------+-----+-------------+ | 1 | 8000 | 7000 | 6000 | ... | null | | 2 | 9000 | null | null | ... | null | | 3 | null | 10000 | null | ... | null | +------+-------------+-------------+-------------+-----+-------------+ Explanation: The revenue from Apr to Dec is null. Note that the result table has 13 columns (1 for the department id + 12 for the months).
