Watch 10 video solutions for Number of Valid Words for Each Puzzle, a hard level problem involving Array, Hash Table, String. This walkthrough by NeetCode has 391,872 views views. Want to try solving it yourself? Practice on FleetCode or read the detailed text solution.
puzzle string, a word is valid if both the following conditions are satisfied:
word contains the first letter of puzzle.word, that letter is in puzzle.
"abcdefg", then valid words are "faced", "cabbage", and "baggage", while"beefed" (does not include 'a') and "based" (includes 's' which is not in the puzzle).answer, where answer[i] is the number of words in the given word list words that is valid with respect to the puzzle puzzles[i].
Example 1:
Input: words = ["aaaa","asas","able","ability","actt","actor","access"], puzzles = ["aboveyz","abrodyz","abslute","absoryz","actresz","gaswxyz"] Output: [1,1,3,2,4,0] Explanation: 1 valid word for "aboveyz" : "aaaa" 1 valid word for "abrodyz" : "aaaa" 3 valid words for "abslute" : "aaaa", "asas", "able" 2 valid words for "absoryz" : "aaaa", "asas" 4 valid words for "actresz" : "aaaa", "asas", "actt", "access" There are no valid words for "gaswxyz" cause none of the words in the list contains letter 'g'.
Example 2:
Input: words = ["apple","pleas","please"], puzzles = ["aelwxyz","aelpxyz","aelpsxy","saelpxy","xaelpsy"] Output: [0,1,3,2,0]
Constraints:
1 <= words.length <= 1054 <= words[i].length <= 501 <= puzzles.length <= 104puzzles[i].length == 7words[i] and puzzles[i] consist of lowercase English letters.puzzles[i] does not contain repeated characters.