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Maximize the Confusion of an Exam - Video Solutions

MediumStringBinary SearchSliding WindowPrefix Sum

Maximize the Confusion of an Exam | 3 Approaches | MICROSOFT | Leetcode-2024 | Explanation

codestorywithMIK
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10 video solutions available

Maximize the Confusion of an Exam - Video Solution

Watch 10 video solutions for Maximize the Confusion of an Exam, a medium level problem involving String, Binary Search, Sliding Window. This walkthrough by codestorywithMIK has 12,179 views views. Want to try solving it yourself? Practice on FleetCode or read the detailed text solution.

Problem Statement

A teacher is writing a test with n true/false questions, with 'T' denoting true and 'F' denoting false. He wants to confuse the students by maximizing the number of consecutive questions with the same answer (multiple trues or multiple falses in a row).

You are given a string answerKey, where answerKey[i] is the original answer to the ith question. In addition, you are given an integer k, the maximum number of times you may perform the following operation:

  • Change the answer key for any question to 'T' or 'F' (i.e., set answerKey[i] to 'T' or 'F').

Return the maximum number of consecutive 'T's or 'F's in the answer key after performing the operation at most k times.

 

Example 1:

Input: answerKey = "TTFF", k = 2
Output: 4
Explanation: We can replace both the 'F's with 'T's to make answerKey = "TTTT".
There are four consecutive 'T's.

Example 2:

Input: answerKey = "TFFT", k = 1
Output: 3
Explanation: We can replace the first 'T' with an 'F' to make answerKey = "FFFT".
Alternatively, we can replace the second 'T' with an 'F' to make answerKey = "TFFF".
In both cases, there are three consecutive 'F's.

Example 3:

Input: answerKey = "TTFTTFTT", k = 1
Output: 5
Explanation: We can replace the first 'F' to make answerKey = "TTTTTFTT"
Alternatively, we can replace the second 'F' to make answerKey = "TTFTTTTT". 
In both cases, there are five consecutive 'T's.

 

Constraints:

  • n == answerKey.length
  • 1 <= n <= 5 * 104
  • answerKey[i] is either 'T' or 'F'
  • 1 <= k <= n
Read full problem with examples

Approach Overview

Problem Overview: You receive a string representing exam answers where each character is 'T' or 'F'. You may change at most k answers. The goal is to maximize the length of a consecutive block of identical answers after performing those changes.

Approach 1: Sliding Window Technique (O(n) time, O(1) space)

The optimal strategy uses a sliding window. Treat the problem as finding the longest substring where you can flip at most k characters to make all values the same. Run the window twice: once assuming the final sequence should be all 'T', and once for 'F'. Expand the right pointer while counting mismatches. When mismatches exceed k, move the left pointer forward and shrink the window. The window size always represents the longest valid segment you can transform with ≤ k flips.

This works because the window always maintains a valid state where the number of required flips is within the allowed limit. Each character is visited at most twice (entering and leaving the window), giving linear complexity. This approach is the standard pattern used in many string optimization problems involving limited modifications.

Approach 2: Two Pointer Technique (O(n) time, O(1) space)

The two pointer method is conceptually the same as sliding window but framed more explicitly with left and right indices. Move the right pointer forward to expand the candidate segment and maintain counts of 'T' and 'F'. When the number of characters needing conversion exceeds k, advance the left pointer to restore validity. The current window length represents a segment that can be converted into all identical answers.

This formulation emphasizes pointer movement and state maintenance rather than a formal window abstraction. It is useful when practicing general pointer techniques used in binary search-style range problems and substring optimization tasks.

Recommended for interviews: The sliding window solution is what most interviewers expect. It demonstrates that you can transform the problem into a longest-valid-substring pattern and maintain constraints efficiently in O(n) time. A brute-force approach that checks all substrings would take O(n²) time and quickly becomes impractical. Showing the transition from brute force thinking to a sliding window optimization demonstrates strong problem-solving skills.

Complexity Analysis

ApproachTimeSpaceWhen to Use
Brute Force (Check All Substrings)O(n²)O(1)Conceptual baseline to understand the problem constraints
Sliding WindowO(n)O(1)Best general solution for longest valid substring with limited modifications
Two Pointer TechniqueO(n)O(1)When implementing substring expansion/shrinking logic using explicit pointer control