Watch 10 video solutions for Data Stream as Disjoint Intervals, a hard level problem involving Binary Search, Design, Ordered Set. This walkthrough by NeetCodeIO has 8,040 views views. Want to try solving it yourself? Practice on FleetCode or read the detailed text solution.
Given a data stream input of non-negative integers a1, a2, ..., an, summarize the numbers seen so far as a list of disjoint intervals.
Implement the SummaryRanges class:
SummaryRanges() Initializes the object with an empty stream.void addNum(int value) Adds the integer value to the stream.int[][] getIntervals() Returns a summary of the integers in the stream currently as a list of disjoint intervals [starti, endi]. The answer should be sorted by starti.
Example 1:
Input ["SummaryRanges", "addNum", "getIntervals", "addNum", "getIntervals", "addNum", "getIntervals", "addNum", "getIntervals", "addNum", "getIntervals"] [[], [1], [], [3], [], [7], [], [2], [], [6], []] Output [null, null, [[1, 1]], null, [[1, 1], [3, 3]], null, [[1, 1], [3, 3], [7, 7]], null, [[1, 3], [7, 7]], null, [[1, 3], [6, 7]]] Explanation SummaryRanges summaryRanges = new SummaryRanges(); summaryRanges.addNum(1); // arr = [1] summaryRanges.getIntervals(); // return [[1, 1]] summaryRanges.addNum(3); // arr = [1, 3] summaryRanges.getIntervals(); // return [[1, 1], [3, 3]] summaryRanges.addNum(7); // arr = [1, 3, 7] summaryRanges.getIntervals(); // return [[1, 1], [3, 3], [7, 7]] summaryRanges.addNum(2); // arr = [1, 2, 3, 7] summaryRanges.getIntervals(); // return [[1, 3], [7, 7]] summaryRanges.addNum(6); // arr = [1, 2, 3, 6, 7] summaryRanges.getIntervals(); // return [[1, 3], [6, 7]]
Constraints:
0 <= value <= 1043 * 104 calls will be made to addNum and getIntervals.102 calls will be made to getIntervals.
Follow up: What if there are lots of merges and the number of disjoint intervals is small compared to the size of the data stream?