Minimum Rounds to Complete All Tasks solution and explanation

def solve_problem(parameters):
    # Base case solution
    if base_condition:
        return
    # Divide
    mid = calculate_middle
    # Conquer
    solve_problem(left_part)
    solve_problem(right_part)
    # Combine
    # combine left and right results

solve_problem(initial_parameters)

public class Solution {
    public void solveProblem(/* parameters */) {
        // Base case solution
        if (/* base condition */) {
            return;
        }
        // Divide
        int mid = /* calculate middle */;
        // Conquer
        solveProblem(/* left part */);
        solveProblem(/* right part */);
        // Combine
        // combine left and right solutions
    }

    public static void main(String[] args) {
        Solution sol = new Solution();
        // Call the method with initial parameters
        sol.solveProblem(/* initial parameters */);
    }
}

#include <iostream>

void solveProblem(/* parameters */) {
    // Base case solution
    if (/* base condition */) {
        return;
    }
    // Divide
    int mid = /* calculate middle */;
    // Conquer
    solveProblem(/* left part */);
    solveProblem(/* right part */);
    // Combine
    // combine left and right solutions
}

int main() {
    // Call the function with initial parameters
    solveProblem(/* initial parameters */);
    return 0;
}

function solveProblem(parameters) {
    // Base case solution
    if (baseCondition) {
        return;
    }
    // Divide
    let mid = calculateMiddle;
    // Conquer
    solveProblem(leftPart);
    solveProblem(rightPart);
    // Combine
    // combine left and right results
}

solveProblem(initialParameters);

#include <stdio.h>

void solveProblem(/* parameters */) {
    // Base case solution
    if (/* base condition */) {
        return;
    }
    // Divide
    int mid = /* calculate middle */;
    // Conquer
    solveProblem(/* left part */);
    solveProblem(/* right part */);
    // Combine
    // combine left and right solutions
}

int main() {
    // Call the function with initial parameters
    solveProblem(/* initial parameters */);
    return 0;
}

class Program {
    static void SolveProblem(/* parameters */) {
        // Base case solution
        if (/* base condition */) {
            return;
        }
        // Divide
        int mid = /* calculate middle */;
        // Conquer
        SolveProblem(/* left part */);
        SolveProblem(/* right part */);
        // Combine
        // combine left and right solutions
    }

    static void Main() {
        SolveProblem(/* initial parameters */);
    }
}

dp = [-1] * 100  # Assume maximum 'n' is 100

def solve_problem(n):
    if n == 0 or n == 1:
        return n
    if dp[n] != -1:
        return dp[n]
    dp[n] = solve_problem(n - 1) + solve_problem(n - 2)
    return dp[n]

n = 10  # Example parameter
print(solve_problem(n))

import java.util.Arrays;

public class Solution {
    static int[] dp = new int[100]; // Initialize with a large enough size

    public static int solveProblem(int n) {
        if (n == 0 || n == 1) return n;
        if (dp[n] != -1) return dp[n];
        dp[n] = solveProblem(n - 1) + solveProblem(n - 2);
        return dp[n];
    }

    public static void main(String[] args) {
        Arrays.fill(dp, -1); // Fill the dp array with -1
        int n = 10;
        System.out.println(solveProblem(n));
    }
}

#include <iostream>
#include <vector>

std::vector<int> dp(100, -1); // Initialize dp array

int solveProblem(int n) {
    if (n == 0 || n == 1) return n;
    if (dp[n] != -1) return dp[n];
    dp[n] = solveProblem(n-1) + solveProblem(n-2);
    return dp[n];
}

int main() {
    int n = 10;
    std::cout << solveProblem(n) << std::endl;
    return 0;
}

let dp = new Array(100).fill(-1);

function solveProblem(n) {
    if (n === 0 || n === 1) return n;
    if (dp[n] !== -1) return dp[n];
    dp[n] = solveProblem(n - 1) + solveProblem(n - 2);
    return dp[n];
}

let n = 10;
console.log(solveProblem(n));

#include <stdio.h>

int dp[100]; // Assuming maximum 'n' is 100 for simplicity

int solveProblem(int n) {
    if (n == 0 || n == 1) return n; // Base cases
    if (dp[n] != -1) return dp[n]; // Check if already computed
    dp[n] = solveProblem(n-1) + solveProblem(n-2);
    return dp[n];
}

int main() {
    int n = 10; // Example parameter
    for (int i = 0; i <= n; i++) dp[i] = -1; // Initialize the dp array
    printf("%d\n", solveProblem(n));
    return 0;
}

using System;

class Program {
    static int[] dp = new int[100]; // Assume maximum 'n' is 100

    static int SolveProblem(int n) {
        if (n == 0 || n == 1) return n;
        if (dp[n] != -1) return dp[n];
        dp[n] = SolveProblem(n - 1) + SolveProblem(n - 2);
        return dp[n];
    }

    static void Main() {
        Array.Fill(dp, -1); // Fill the array with -1
        int n = 10;
        Console.WriteLine(SolveProblem(n));
    }
}

function minimumRounds(tasks: number[]): number {
    const cnt = new Map();
    for (const t of tasks) {
        cnt.set(t, (cnt.get(t) || 0) + 1);
    }
    let ans = 0;
    for (const v of cnt.values()) {
        if (v == 1) {
            return -1;
        }
        ans += Math.floor(v / 3) + (v % 3 === 0 ? 0 : 1);
    }
    return ans;
}

func minimumRounds(tasks []int) int {
	cnt := map[int]int{}
	for _, t := range tasks {
		cnt[t]++
	}
	ans := 0
	for _, v := range cnt {
		if v == 1 {
			return -1
		}
		ans += v / 3
		if v%3 != 0 {
			ans++
		}
	}
	return ans
}

use std::collections::HashMap;

impl Solution {
    pub fn minimum_rounds(tasks: Vec<i32>) -> i32 {
        let mut cnt = HashMap::new();
        for &t in tasks.iter() {
            let count = cnt.entry(t).or_insert(0);
            *count += 1;
        }
        let mut ans = 0;
        for &v in cnt.values() {
            if v == 1 {
                return -1;
            }
            ans += v / 3 + (if v % 3 == 0 { 0 } else { 1 });
        }
        ans
    }
}