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Minimum Partition Score - Solution & Explanation

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Problem Statement

You are given an integer array nums and an integer k.

Your task is to partition nums into exactly k subarrays and return an integer denoting the minimum possible score among all valid partitions.

The score of a partition is the sum of the values of all its subarrays.

The value of a subarray is defined as sumArr * (sumArr + 1) / 2, where sumArr is the sum of its elements.

 

Example 1:

Input: nums = [5,1,2,1], k = 2

Output: 25

Explanation:

  • We must partition the array into k = 2 subarrays. One optimal partition is [5] and [1, 2, 1].
  • The first subarray has sumArr = 5 and value = 5 × 6 / 2 = 15.
  • The second subarray has sumArr = 1 + 2 + 1 = 4 and value = 4 × 5 / 2 = 10.
  • The score of this partition is 15 + 10 = 25, which is the minimum possible score.

Example 2:

Input: nums = [1,2,3,4], k = 1

Output: 55

Explanation:

  • Since we must partition the array into k = 1 subarray, all elements belong to the same subarray: [1, 2, 3, 4].
  • This subarray has sumArr = 1 + 2 + 3 + 4 = 10 and value = 10 × 11 / 2 = 55.​​​​​​​
  • The score of this partition is 55, which is the minimum possible score.

Example 3:

Input: nums = [1,1,1], k = 3

Output: 3

Explanation:

  • We must partition the array into k = 3 subarrays. The only valid partition is [1], [1], [1].
  • Each subarray has sumArr = 1 and value = 1 × 2 / 2 = 1.
  • The score of this partition is 1 + 1 + 1 = 3, which is the minimum possible score.

 

Constraints:

  • 1 <= nums.length <= 1000
  • 1 <= nums[i] <= 104
  • 1 <= k <= nums.length

Approach Overview

Problem Overview: You are given an array and must split it into multiple contiguous partitions so the total partition score is minimized. Each partition contributes a score based on the values inside the segment, and the goal is to choose split points that produce the smallest total score.

Approach 1: Brute Force Partition Enumeration (O(n^3) time, O(1) space)

The most direct way is to try every possible partitioning. For every pair of indices i and j, treat nums[i..j] as a segment and compute its score by scanning the subarray. Then recursively evaluate the remaining suffix. This approach repeatedly recomputes segment statistics such as minimum and maximum values, which leads to cubic time. It helps understand the partition structure but becomes infeasible once the array size grows.

Approach 2: Dynamic Programming with Precomputed Segment Scores (O(n^2) time, O(n) space)

Define dp[i] as the minimum score required to partition the prefix ending at index i. For each i, iterate over all previous split points j and evaluate the cost of the segment nums[j+1..i]. The transition becomes dp[i] = min(dp[j] + cost(j+1, i)). Segment statistics such as minimum, maximum, or sum can be tracked incrementally using techniques from array processing and prefix sum preprocessing. This reduces redundant work but still checks every possible split, resulting in quadratic time.

Approach 3: Monotonic Queue Optimized DP (O(n) time, O(n) space)

The optimal approach observes that segment scores depend on monotonic properties such as the minimum or maximum value within the current window. Instead of recomputing them for every candidate split, maintain two monotonic queues that track increasing and decreasing elements as the right boundary moves. While extending the segment, update the structures so the current min/max can be retrieved in constant time. Combine this with a rolling DP transition so outdated partition candidates are removed when they stop producing optimal scores. The monotonic behavior allows each element to be pushed and popped at most once, giving linear complexity.

This technique combines ideas from dynamic programming and monotonic queue optimization. Instead of scanning all previous split points, the queue maintains only candidates that can still produce the best score for upcoming indices.

Recommended for interviews: Start by describing the DP formulation because it clearly expresses how partitions contribute to the final score. Interviewers expect you to recognize that checking every split leads to O(n^2) work. The strong signal is identifying the monotonic property in the segment score and applying a monotonic queue to compress transitions to O(n). That shift from quadratic DP to linear optimization demonstrates strong problem‑solving ability.

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Detailed Complexity Analysis

ApproachTimeSpaceWhen to Use
Brute Force Partition EnumerationO(n^3)O(1)Useful only for understanding how partition scores are computed
Dynamic Programming with Segment TrackingO(n^2)O(n)General DP solution when constraints allow quadratic time
DP with Monotonic Queue OptimizationO(n)O(n)Optimal solution for large arrays where segment scores follow monotonic behavior

Video Solution

Leetcode 3826 | Minimum Partition Score | Beginner Friendly | Dynamic Programming • CodeWithMeGuys • 694 views views

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Frequently Asked Questions

Is Minimum Partition Score easy or hard?
Minimum Partition Score is considered a Hard problem because it combines multiple advanced concepts: dynamic programming, segment cost evaluation, and monotonic queue optimization. Recognizing the DP structure is manageable, but reducing the complexity from O(n^2) to O(n) requires deeper insight.
Minimum Partition Score Python/Java solution
The typical implementation uses dynamic programming with a deque-based monotonic queue. The same algorithm works across Python, Java, C++, and Go with minor syntax differences. Each language maintains a deque structure to keep candidate indices while updating the DP array.
How to solve Minimum Partition Score in O(n)?
Formulate the problem as dp[i] representing the minimum score to partition the first i elements. Maintain monotonic queues that track relevant segment properties while expanding the right boundary of the partition. As the window grows, update DP transitions and discard suboptimal candidates from the queue so each element is processed only once.
What is the best approach for Minimum Partition Score?
The best approach uses dynamic programming optimized with a monotonic queue. A DP array tracks the minimum score for each prefix, while monotonic queues maintain segment statistics such as min or max values efficiently. This removes the need to check every previous split and reduces the complexity to O(n) time with O(n) space.
Is Minimum Partition Score asked at Google/Amazon/Meta?
Problems involving partition DP combined with monotonic queues appear frequently in interviews at large tech companies such as Google, Amazon, and Meta. The exact problem may vary, but the pattern of optimizing dynamic programming transitions using monotonic data structures is a common advanced interview topic.
What data structure is used in Minimum Partition Score?
The optimized solution uses a monotonic queue along with dynamic programming and prefix-based calculations. The monotonic queue maintains ordered candidates for segment statistics like minimum or maximum values, allowing constant time updates while scanning the array.
What is the time complexity of Minimum Partition Score?
The optimal solution runs in O(n) time using a monotonic queue optimized dynamic programming approach. Each array element is inserted and removed from the queue at most once, which keeps the operations linear. The DP array requires O(n) space.

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