Maximum Odd Binary Number - Solution & Explanation

To form the maximum odd binary number from a given binary string, observe that the binary number should have '1' at the end to be odd. Among the remaining bits, arrange as many '1's as possible at the leading positions while maintaining the '1' at the end. This approach involves counting the occurrences of '1' and '0', then constructing the number.

1. Count the '1's and '0's in the string.
2. Ensure the last bit is '1', then place the rest of the '1's at the beginning and fill with '0's.

The program first counts the '1's and '0's. It reserves one '1' for the end to make the number odd. The rest of the '1's are placed at the beginning, and '0's fill the remaining positions before the final '1'.

A different approach involves sorting the binary string while ensuring a '1' is at the end. To maximize the binary number, the initial part of the string should consist of leading '1's followed by '0's, then append a single '1' at the end to turn the number odd.

1. Convert the string to a list and sort in descending order.
2. Ensure the last position is '1'.

This solution sorts the string in descending order and ensures '1' is moved to the last position. Sorting places '1's before '0's. The trailing '1' ensures oddness.