Goal Parser Interpretation solution and explanation
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The problem
You own a Goal Parser that can interpret a string command. The command consists of an alphabet of "G", "()" and/or "(al)" in some order. The Goal Parser will interpret "G" as the string "G", "()" as the string "o", and "(al)" as the string "al". The interpreted strings are then concatenated in the original order.
Given the string command, return the Goal Parser's interpretation of command.
Example 1:
Input: command = "G()(al)" Output: "Goal" Explanation: The Goal Parser interprets the command as follows: G -> G () -> o (al) -> al The final concatenated result is "Goal".
Example 2:
Input: command = "G()()()()(al)" Output: "Gooooal"
Example 3:
Input: command = "(al)G(al)()()G" Output: "alGalooG"
Constraints:
1 <= command.length <= 100commandconsists of"G","()", and/or"(al)"in some order.
Approach overview
Problem Overview: You receive a command string used by the Goal Parser. The parser interprets patterns using simple rules: "G" -> "G", "()" -> "o", and "(al)" -> "al". The task is to scan the input command and return the interpreted string after applying these mappings.
This problem is fundamentally a string parsing task. The input contains predictable patterns, so the goal is simply to recognize them efficiently while traversing the string once.
Approach 1: String Replacement (O(n) time, O(n) space)
The most direct solution replaces the known patterns with their interpreted values. Since the command only contains three valid tokens (G, (), and (al)), you can apply sequential string replacements: replace () with o and (al) with al. After replacements, the remaining characters are already valid output.
Another variation scans the string using an index pointer. When you encounter 'G', append it to the result. If you see '(', check the next characters: () becomes "o", while (al) becomes "al". Move the pointer accordingly. Each character is processed once, giving O(n) time complexity and O(n) space for the output string.
This approach works because the grammar is fixed and non-overlapping. There is no ambiguity, so simple conditional checks or replacement operations are sufficient. For interview settings, the pointer-based scan demonstrates clear understanding of string manipulation and avoids unnecessary intermediate copies.
Approach 2: Pattern Matching with Regular Expressions (O(n) time, O(n) space)
You can also solve the problem using regular expressions. Define a pattern that matches \(\) and \(al\), then replace them with their interpreted values. Regex engines efficiently scan the string and apply substitutions in a single pass.
For example, perform two replacements: convert () to "o", then convert (al) to "al". Most modern regex implementations run in linear time for this type of fixed pattern matching, resulting in O(n) time complexity with O(n) additional space for the transformed string.
This approach is concise and expressive, especially in languages like Python or JavaScript where regex replacements are built-in. However, interviewers often prefer explicit parsing logic because it demonstrates control over string traversal and avoids reliance on regex libraries.
Recommended for interviews: Use the pointer-based string scan from the String Replacement approach. It processes the input once in O(n) time with O(n) space, clearly shows how you identify tokens like () and (al), and avoids unnecessary library calls. The regex approach is shorter but hides the parsing logic, which interviewers usually want to see.
Approach 1: String Replacement
String Replacement Approach
In this approach, the idea is to replace all occurrences of '()' with 'o' and '(al)' with 'al' in the command string. Since 'G' should remain unchanged, we can use direct replacements to generate the interpreted output.
We can perform these replacements in a single pass, or even within a loop through the string, where we gradually build the output string by detecting patterns and appending the respective characters.
def interpret(command: str) -> str:
result = []
i = 0
while i < len(command):
if command[i] == 'G':
result.append('G')
i += 1
elif command[i:i+2] == '()':
result.append('o')
i += 2
else:
result.append('al')
i += 4
return ''.join(result)public class GoalParser {
public String interpret(String command) {
StringBuilder result = new StringBuilder();
for (int i = 0; i < command.length(); i++) {
if (command.charAt(i) == 'G') {
result.append('G');
} else if (command.charAt(i) == '(') {
if (command.charAt(i + 1) == ')') {
result.append('o');
i++; // Skip ) character
} else {
result.append("al");
i += 3; // Skip 'al)' characters
}
}
}
return result.toString();
}
}#include <string>
using namespace std;
string interpret(string command) {
string result;
for (size_t i = 0; i < command.length(); ++i) {
if (command[i] == 'G') {
result += 'G';
} else if (command[i] == '(') {
if (command[i + 1] == ')') {
result += 'o';
i++; // Skip next character
} else {
result += "al";
i += 3; // Skip next three characters
}
}
}
return result;
}function interpret(command) {
let result = '';
for (let i = 0; i < command.length; i++) {
if (command[i] === 'G') {
result += 'G';
} else if (command[i] === '(') {
if (command[i + 1] === ')') {
result += 'o';
i++; // Skip the ')' character
} else {
result += 'al';
i += 3; // Skip the 'al)'
}
}
}
return result;
}#include <stdio.h>
#include <string.h>
char* interpret(char* command) {
static char result[101];
int j = 0;
for (int i = 0; command[i] != '\0'; i++) {
if (command[i] == 'G') {
result[j++] = 'G';
} else if (command[i] == '(' && command[i + 1] == ')') {
result[j++] = 'o';
i++; // Skip the next character
} else if (command[i] == '(' && command[i + 1] == 'a') {
result[j++] = 'a';
result[j++] = 'l';
i += 3; // Skip the next three characters
}
}
result[j] = '\0';
return result;
}public class Solution {
public string Interpret(string command) {
var result = new System.Text.StringBuilder();
for (int i = 0; i < command.Length; i++) {
if (command[i] == 'G') {
result.Append('G');
} else if (command[i] == '(') {
if (command[i + 1] == ')') {
result.Append('o');
i++; // Skip the next character
} else {
result.Append("al");
i += 3; // Skip the next three characters
}
}
}
return result.ToString();
}
}The Python solution uses a list result to build the result efficiently. It iterates over the command string using a while loop with index i:
- When encountering 'G', it appends 'G' to
result. - If '()' is found, it appends 'o' and skips two characters.
- For '(al)', it appends 'al' and skips four characters.
Time Complexity: O(n), where n is the length of the command string.
Space Complexity: O(n), due to the resulting list storage.
Approach 2: Pattern Matching with Regular Expressions
Pattern Matching Using Regular Expressions
In this approach, we utilize regular expressions to match and replace the specific patterns in the command string. This is a more concise approach that is generally supported by languages like Python and can simplify the transformation steps considerably.
We can replace all instances of '()' with 'o' and '(al)' with 'al' using regular expressions, then return the transformed string.
import re
def interpret(command: str) -> str:
return re.sub(r'\(\)', 'o', re.sub(r'\(al\)', 'al', command))function interpret(command) {
return command.replace(/\(\)/g, 'o').replace(/\(al\)/g, 'al');
}This Python solution employs the re.sub function from the regular expressions library to perform sequential replacements:
re.sub(r'\(\)', 'o', command)replaces '()' with 'o'.re.sub(r'\(al\)', 'al', command)replaces '(al)' with 'al'.- Both transformations occur in a nested manner to simplify the original
command.
Time Complexity: O(n), as the regular expression operations on a string with n-length have similar complexity.
Space Complexity: O(n), given the construction of a new string.
Approach 3: String Replacement
According to the problem, we only need to replace "()" with 'o' and "(al)" with "al" in the string command.
function interpret(command: string): string {
return command.replace(/\(\)/g, 'o').replace(/\(al\)/g, 'al');
}func interpret(command string) string {
command = strings.ReplaceAll(command, "()", "o")
command = strings.ReplaceAll(command, "(al)", "al")
return command
}impl Solution {
pub fn interpret(command: String) -> String {
command.replace("()", "o").replace("(al)", "al")
}
}Approach 4: String Iteration
We can also iterate over the string command. For each character c:
- If it is
'G', directly addcto the result string; - If it is
'(', check if the next character is')'. If it is, add'o'to the result string. Otherwise, add"al"to the result string.
After the iteration, return the result string.
The time complexity is O(n), and the space complexity is O(1).
function interpret(command: string): string {
const n = command.length;
const ans: string[] = [];
for (let i = 0; i < n; i++) {
const c = command[i];
if (c === 'G') {
ans.push(c);
} else if (c === '(') {
ans.push(command[i + 1] === ')' ? 'o' : 'al');
}
}
return ans.join('');
}func interpret(command string) string {
ans := &strings.Builder{}
for i, c := range command {
if c == 'G' {
ans.WriteRune(c)
} else if c == '(' {
if command[i+1] == ')' {
ans.WriteByte('o')
} else {
ans.WriteString("al")
}
}
}
return ans.String()
}impl Solution {
pub fn interpret(command: String) -> String {
let mut ans = String::new();
let bs = command.as_bytes();
for i in 0..bs.len() {
if bs[i] == b'G' {
ans.push_str("G");
}
if bs[i] == b'(' {
ans.push_str({
if bs[i + 1] == b')' {
"o"
} else {
"al"
}
});
}
}
ans
}
}Complexity comparison
| Approach | Complexity |
|---|---|
| String Replacement | Time Complexity: O(n), where n is the length of the command string. Space Complexity: O(n), due to the resulting list storage. |
| Pattern Matching with Regular Expressions | Time Complexity: O(n), as the regular expression operations on a string with n-length have similar complexity. Space Complexity: O(n), given the construction of a new string. |
| String Replacement | – |
| String Iteration | – |
Complexity analysis
| Approach | Time | Space | When to Use |
|---|---|---|---|
| String Replacement / Pointer Scan | O(n) | O(n) | Best general solution. Clear logic and preferred in coding interviews. |
| Regular Expression Replacement | O(n) | O(n) | Useful for concise implementations when regex support is convenient. |
Frequently asked questions
Is Goal Parser Interpretation easy or hard?
Goal Parser Interpretation is rated Easy. The problem focuses on recognizing fixed string patterns and implementing a clean linear scan, making it a common beginner-friendly question for practicing string manipulation.
Goal Parser Interpretation Python/Java solution
In Python or Java, the typical solution iterates through the string and appends interpreted tokens to a result builder. Python often uses a list or string concatenation, while Java typically uses StringBuilder. Both implementations run in O(n) time and O(n) space.
How to solve Goal Parser Interpretation in O(n)?
Traverse the string with an index pointer. When you see 'G', append 'G' to the result. If you encounter '(', check whether the next characters form '()' or '(al)' and append 'o' or 'al' respectively. Move the pointer forward by the length of the matched token. This processes the entire string in one pass.
What is the best approach for Goal Parser Interpretation?
The best approach is a single-pass string scan. Iterate through the command string and interpret tokens as you encounter them: 'G' stays 'G', '()' becomes 'o', and '(al)' becomes 'al'. This method runs in O(n) time and uses O(n) space for the output string while keeping the logic simple and interview-friendly.
Is Goal Parser Interpretation asked at Google/Amazon/Meta?
Goal Parser Interpretation is categorized as an easy string parsing problem. Similar string manipulation and token parsing questions appear in interviews at companies like Amazon, Google, and Meta, especially in early interview rounds to test basic problem-solving and coding clarity.
What data structure is used in Goal Parser Interpretation?
The problem primarily uses basic string operations. Most solutions build the result using a mutable string builder or list buffer, then convert it to a final string. No advanced data structures are required beyond simple indexing and concatenation.
What is the time complexity of Goal Parser Interpretation?
The optimal solution runs in O(n) time, where n is the length of the command string. Each character is examined at most once while parsing patterns like '()', '(al)', or 'G'. The space complexity is O(n) because the interpreted output string must be stored.
