In the world of Dota2, there are two parties: the Radiant and the Dire.
The Dota2 senate consists of senators coming from two parties. Now the Senate wants to decide on a change in the Dota2 game. The voting for this change is a round-based procedure. In each round, each senator can exercise one of the two rights:
Given a string senate representing each senator's party belonging. The character 'R' and 'D' represent the Radiant party and the Dire party. Then if there are n senators, the size of the given string will be n.
The round-based procedure starts from the first senator to the last senator in the given order. This procedure will last until the end of voting. All the senators who have lost their rights will be skipped during the procedure.
Suppose every senator is smart enough and will play the best strategy for his own party. Predict which party will finally announce the victory and change the Dota2 game. The output should be "Radiant" or "Dire".
Example 1:
Input: senate = "RD" Output: "Radiant" Explanation: The first senator comes from Radiant and he can just ban the next senator's right in round 1. And the second senator can't exercise any rights anymore since his right has been banned. And in round 2, the first senator can just announce the victory since he is the only guy in the senate who can vote.
Example 2:
Input: senate = "RDD" Output: "Dire" Explanation: The first senator comes from Radiant and he can just ban the next senator's right in round 1. And the second senator can't exercise any rights anymore since his right has been banned. And the third senator comes from Dire and he can ban the first senator's right in round 1. And in round 2, the third senator can just announce the victory since he is the only guy in the senate who can vote.
Constraints:
n == senate.length1 <= n <= 104senate[i] is either 'R' or 'D'.Problem Overview: You are given a string where each character represents a senator from the Radiant (R) or Dire (D) party. Senators take turns banning opponents. Once banned, a senator cannot vote in future rounds. The process continues in rounds until only one party remains with active senators. Your task is to predict which party wins.
Approach 1: Direct Round Simulation (O(n^2) time, O(n) space)
The most straightforward idea is to simulate the voting rounds exactly as described. Iterate through the string in a circular manner. When a senator appears, check whether they still have the right to vote. If so, ban the next available opponent by marking them inactive. Continue looping until all remaining active senators belong to the same party.
This approach mirrors the problem statement but repeatedly scans the array to find the next valid opponent. In the worst case, each senator might trigger a long search across the list. That repeated scanning pushes the time complexity to O(n^2). The space cost stays O(n) because you maintain the senate state and banned markers.
Approach 2: Queue Simulation with Indices (O(n) time, O(n) space)
The optimized strategy treats the process as a turn-based competition using two queues. Store the indices of Radiant senators in one queue and Dire senators in another. Each round compares the front elements of both queues. The senator with the smaller index acts first and bans the opponent.
After banning, the acting senator returns to the queue with an updated index of currentIndex + n. This represents the next round because the senate order wraps around. The banned senator simply disappears from the process. Continue until one queue becomes empty.
This method avoids scanning for opponents. Each senator enters and leaves the queue a limited number of times, giving an overall time complexity of O(n) and space complexity of O(n). The behavior is essentially a greedy turn scheduling problem using a queue. The input itself is a string, and the decision rule follows a greedy principle: whoever appears earlier in the current round gets priority to ban.
Recommended for interviews: Interviewers typically expect the queue simulation approach. The brute-force round simulation shows that you understand the mechanics of the problem, but the index-based queue solution demonstrates stronger algorithmic thinking. It converts a circular voting process into a clean greedy scheduling problem and reduces the complexity from quadratic to linear.
We utilize two separate queues to maintain indices of Radiant and Dire senators. In each round, senators from both parties execute their rights and effect bans on their opponent. The process continues until one queue becomes empty, indicating that all senators from one party have been eliminated.
In the solution, we employ a queue to separately track Radiant and Dire senators' indices. For each senate round, we compare indices of both parties. The senator with a smaller index, indicating an earlier position, bans the other and gets scheduled for the next round with an increased index (index + senate length). The queue that first becomes empty indicates the losing party.
Time Complexity: O(n), where n is the length of the senate, since each senator is processed a finite number of times.
Space Complexity: O(n), for storing indices in queues.
| Approach | Time | Space | When to Use |
|---|---|---|---|
| Direct Round Simulation | O(n^2) | O(n) | Useful for understanding the rules and basic simulation before optimizing |
| Queue Simulation with Indices | O(n) | O(n) | Best approach for interviews and large inputs; avoids repeated scanning |
Dota2 Senate - Leetcode 649 - Python • NeetCodeIO • 34,528 views views
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