Count Complete Subarrays in an Array - Solution & Explanation

This approach uses a sliding window technique in combination with a HashMap (or dictionary) to keep track of the distinct elements within the window.

1. First, count the number of distinct elements in the whole array.
2. Use two pointers, start and end, to define the window's range, and a HashMap to track the frequency of elements within this window.
3. Expand the window by moving the end pointer and update the map to add the frequency of the element. Keep track of the number of distinct elements using a counter.
4. If the window contains the same number of distinct elements as the entire array, try shrinking the window from the left by moving the start pointer, updating the map, and counting the subarrays formed.
5. Repeat until the end pointer reaches the end of the array.

The solution uses a sliding window technique to efficiently count complete subarrays. It maintains a dictionary to hold the frequency of each element in the current window and counts the complete subarrays dynamically by shrinking the window from the left when a complete subarray is found.