You are given an integer n.
A number is called digitorial if the sum of the factorials of its digits is equal to the number itself.
Determine whether any permutation of n (including the original order) forms a digitorial number.
Return true if such a permutation exists, otherwise return false.
Note:
x, denoted as x!, is the product of all positive integers less than or equal to x, and 0! = 1.
Example 1:
Input: n = 145
Output: true
Explanation:
The number 145 itself is digitorial since 1! + 4! + 5! = 1 + 24 + 120 = 145. Thus, the answer is true.
Example 2:
Input: n = 10
Output: false
Explanation:
10 is not digitorial since 1! + 0! = 2 is not equal to 10, and the permutation "01" is invalid because it starts with zero.
Constraints:
1 <= n <= 109Solutions for this problem are being prepared.
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