139. Word Break
Given a string s and a dictionary of strings wordDict, return true if s can be segmented into a space-separated sequence of one or more dictionary words.
Note that the same word in the dictionary may be reused multiple times in the segmentation.
Example 1:
Input: s = "leetcode", wordDict = ["leet","code"] Output: true Explanation: Return true because "leetcode" can be segmented as "leet code".
Example 2:
Input: s = "applepenapple", wordDict = ["apple","pen"] Output: true Explanation: Return true because "applepenapple" can be segmented as "apple pen apple". Note that you are allowed to reuse a dictionary word.
Example 3:
Input: s = "catsandog", wordDict = ["cats","dog","sand","and","cat"] Output: false
Constraints:
1 <= s.length <= 3001 <= wordDict.length <= 10001 <= wordDict[i].length <= 20sandwordDict[i]consist of only lowercase English letters.- All the strings of
wordDictare unique.
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1class Solution:
2 def wordBreak(self, s: str, wordDict: List[str]) -> bool:
3
Starter codePython 3Spaces: 4
Loading editor…
1class Solution:
2 def wordBreak(self, s: str, wordDict: List[str]) -> bool:
3
Starter codePython 3Spaces: 4
Examples
Input
"leetcode" ["leet","code"]
Input
"applepenapple" ["apple","pen"]
Input
"catsandog" ["cats","dog","sand","and","cat"]
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