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FleetCode

1721. Swapping Nodes in a Linked List

Medium69.9% acceptance6 companies

You are given the head of a linked list, and an integer k.

Return the head of the linked list after swapping the values of the kth node from the beginning and the kth node from the end (the list is 1-indexed).

Example 1:

Input: head = [1,2,3,4,5], k = 2
Output: [1,4,3,2,5]

Example 2:

Input: head = [7,9,6,6,7,8,3,0,9,5], k = 5
Output: [7,9,6,6,8,7,3,0,9,5]

Constraints:

  • The number of nodes in the list is n.
  • 1 <= k <= n <= 105
  • 0 <= Node.val <= 100

Hints open one at a time

Hint 1
We can traverse the linked list and store the elements in an array.
Hint 2
Upon conversion to an array, we can swap the required elements by indexing the array.
Hint 3
We can rebuild the linked list using the order of the elements in the array.
5:31
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1# Definition for singly-linked list.
2# class ListNode:
3# def __init__(self, val=0, next=None):
4# self.val = val
5# self.next = next
6class Solution:
7 def swapNodes(self, head: Optional[ListNode], k: int) -> Optional[ListNode]:
8
Starter codePython 3Spaces: 4
Examples
Input
[1,2,3,4,5]
2
Input
[7,9,6,6,7,8,3,0,9,5]
5
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