Is Sum of Integers with Maximum Digit Range easy or hard?

The problem is generally categorized as Easy because the core logic relies on simple digit traversal and comparison. The main challenge is correctly updating the maximum range and handling ties while maintaining the final sum.

Sum of Integers with Maximum Digit Range Python/Java solution

Python solutions usually use modulo and floor division to extract digits efficiently inside a loop. Java implementations follow the same logic with integer arithmetic and constant extra memory, making both languages suitable for an O(n * k) implementation.

How to solve Sum of Integers with Maximum Digit Range in O(n)?

If the maximum number of digits is treated as a constant, the solution behaves like O(n). Iterate through the array once, compute the digit range for every number, update the current maximum range, and maintain the running sum for matching integers.

What is the best approach for Sum of Integers with Maximum Digit Range?

The best approach is a single-pass traversal that computes the digit range for each number while tracking the current maximum range and accumulated sum. It runs in O(n * k) time, where k is the number of digits per integer, and uses O(1) extra space.

Is Sum of Integers with Maximum Digit Range asked at Google/Amazon/Meta?

Digit-processing and number-analysis problems appear frequently in coding interviews at companies like Amazon, Google, and Meta. Variants often test implementation accuracy, edge-case handling, and optimization of repeated numeric operations.

What data structure is used in Sum of Integers with Maximum Digit Range?

The problem typically does not require advanced data structures. Most solutions rely on integer arithmetic, loop traversal, and a few scalar variables for tracking the current maximum digit range and result sum.

What is the time complexity of Sum of Integers with Maximum Digit Range?

The optimal solution runs in O(n * k) time because each integer must be processed digit by digit. Space complexity is O(1) since only a few tracking variables are needed during traversal.

Description Hints 2 Solution Video 3:30

3982. Sum of Integers with Maximum Digit Range

Easy72.9% acceptance

You are given an integer array nums.

The digit range of an integer is defined as the difference between its largest digit and smallest digit.

For example, the digit range of 5724 is 7 - 2 = 5.

Return the sum of all integers in nums whose digit range is equal to the maximum digit range among all integers in the array.

Example 1:

Input: nums = [5724,111,350]

Output: 6074

Explanation:

`i`	`nums[i]`	Largest	Smallest	Digit Range
0	5724	7	2	5
1	111	1	1	0
2	350	5	0	5

The maximum digit range is 5. The integers with this digit range are 5724 and 350, so the answer is 5724 + 350 = 6074.

Example 2:

Input: nums = [90,900]

Output: 990

Explanation:

`i`	`nums[i]`	Largest	Smallest	Digit Range
0	90	9	0	9
1	900	9	0	9

The maximum digit range is 9. Both integers have this digit range, so the answer is 90 + 900 = 990.

Constraints:

1 <= nums.length <= 100
10 <= nums[i] <= 10⁵

Topics

Array Math

Hints open one at a time

Hint 1

Compute the digit range of each number by scanning its decimal digits.

Hint 2

First find the maximum digit range, then sum all numbers whose digit range equals it.

3:30

Still stuck?Read the written solution, or watch a walkthrough.

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1class Solution:
2    def maxDigitRange(self, nums: list[int]) -> int:
3        

Starter codePython 3Spaces: 4

Examples

Case 1Case 2

Input

[5724,111,350]

Input

[90,900]

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