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2012. Sum of Beauty in the Array

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You are given a 0-indexed integer array nums. For each index i (1 <= i <= nums.length - 2) the beauty of nums[i] equals:

  • 2, if nums[j] < nums[i] < nums[k], for all 0 <= j < i and for all i < k <= nums.length - 1.
  • 1, if nums[i - 1] < nums[i] < nums[i + 1], and the previous condition is not satisfied.
  • 0, if none of the previous conditions holds.

Return the sum of beauty of all nums[i] where 1 <= i <= nums.length - 2.

Example 1:

Input: nums = [1,2,3]
Output: 2
Explanation: For each index i in the range 1 <= i <= 1:
- The beauty of nums[1] equals 2.

Example 2:

Input: nums = [2,4,6,4]
Output: 1
Explanation: For each index i in the range 1 <= i <= 2:
- The beauty of nums[1] equals 1.
- The beauty of nums[2] equals 0.

Example 3:

Input: nums = [3,2,1]
Output: 0
Explanation: For each index i in the range 1 <= i <= 1:
- The beauty of nums[1] equals 0.

Constraints:

  • 3 <= nums.length <= 105
  • 1 <= nums[i] <= 105

Asked at 1 company

Topics

Hints open one at a time

Hint 1
Use suffix/prefix arrays.
Hint 2
prefix[i] records the maximum value in range (0, i - 1) inclusive.
Hint 3
suffix[i] records the minimum value in range (i + 1, n - 1) inclusive.
10:13
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1class Solution:
2 def sumOfBeauties(self, nums: List[int]) -> int:
3
Starter codePython 3Spaces: 4
Examples
Input
[1,2,3]
Input
[2,4,6,4]
Input
[3,2,1]
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