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2046. Sort Linked List Already Sorted Using Absolute Values

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Given the head of a singly linked list that is sorted in non-decreasing order using the absolute values of its nodes, return the list sorted in non-decreasing order using the actual values of its nodes.

Example 1:

Input: head = [0,2,-5,5,10,-10]
Output: [-10,-5,0,2,5,10]
Explanation:
The list sorted in non-descending order using the absolute values of the nodes is [0,2,-5,5,10,-10].
The list sorted in non-descending order using the actual values is [-10,-5,0,2,5,10].

Example 2:

Input: head = [0,1,2]
Output: [0,1,2]
Explanation:
The linked list is already sorted in non-decreasing order.

Example 3:

Input: head = [1]
Output: [1]
Explanation:
The linked list is already sorted in non-decreasing order.

Constraints:

  • The number of nodes in the list is the range [1, 105].
  • -5000 <= Node.val <= 5000
  • head is sorted in non-decreasing order using the absolute value of its nodes.
Follow up:
  • Can you think of a solution with O(n) time complexity?

Hints open one at a time

Hint 1
The nodes with positive values are already in the correct order.
Hint 2
Nodes with negative values need to be moved to the front.
Hint 3
Nodes with negative values are in reversed order.
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Starter codePython 3Spaces: 4
Examples
Input
[0,2,-5,5,10,-10]
Input
[0,1,2]
Input
[1]
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