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2336. Smallest Number in Infinite Set

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You have a set which contains all positive integers [1, 2, 3, 4, 5, ...].

Implement the SmallestInfiniteSet class:

  • SmallestInfiniteSet() Initializes the SmallestInfiniteSet object to contain all positive integers.
  • int popSmallest() Removes and returns the smallest integer contained in the infinite set.
  • void addBack(int num) Adds a positive integer num back into the infinite set, if it is not already in the infinite set.

Example 1:

Input
["SmallestInfiniteSet", "addBack", "popSmallest", "popSmallest", "popSmallest", "addBack", "popSmallest", "popSmallest", "popSmallest"]
[[], [2], [], [], [], [1], [], [], []]
Output
[null, null, 1, 2, 3, null, 1, 4, 5]

Explanation
SmallestInfiniteSet smallestInfiniteSet = new SmallestInfiniteSet();
smallestInfiniteSet.addBack(2);    // 2 is already in the set, so no change is made.
smallestInfiniteSet.popSmallest(); // return 1, since 1 is the smallest number, and remove it from the set.
smallestInfiniteSet.popSmallest(); // return 2, and remove it from the set.
smallestInfiniteSet.popSmallest(); // return 3, and remove it from the set.
smallestInfiniteSet.addBack(1);    // 1 is added back to the set.
smallestInfiniteSet.popSmallest(); // return 1, since 1 was added back to the set and
                                   // is the smallest number, and remove it from the set.
smallestInfiniteSet.popSmallest(); // return 4, and remove it from the set.
smallestInfiniteSet.popSmallest(); // return 5, and remove it from the set.

Constraints:

  • 1 <= num <= 1000
  • At most 1000 calls will be made in total to popSmallest and addBack.

Hints open one at a time

Hint 1
Based on the constraints, what is the maximum element that can possibly be popped?
Hint 2
Maintain whether elements are in or not in the set. How many elements do we consider?
31:08
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Open solution
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1class SmallestInfiniteSet:
2
3 def __init__(self):
4
5
6 def popSmallest(self) -> int:
7
8
9 def addBack(self, num: int) -> None:
10
11
12
13# Your SmallestInfiniteSet object will be instantiated and called as such:
14# obj = SmallestInfiniteSet()
15# param_1 = obj.popSmallest()
16# obj.addBack(num)
Starter codePython 3Spaces: 4
Examples
Input
["SmallestInfiniteSet","addBack","popSmallest","popSmallest","popSmallest","addBack","popSmallest","popSmallest","popSmallest"]
[[],[2],[],[],[],[1],[],[],[]]
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