Is Smallest Divisible Digit Product I easy or hard?

Smallest Divisible Digit Product I is classified as an Easy problem on LeetCode with an acceptance rate above 60%. It mainly tests digit manipulation, basic math operations, and careful iteration with small optimizations.

Smallest Divisible Digit Product I Python/Java solution

In Python or Java, iterate from n upward and compute the product of digits using modulo and division operations. Check product % t == 0 for each candidate and return the first valid number. The implementation uses constant extra space and simple loops.

How to solve Smallest Divisible Digit Product I in O(n)?

Treat the problem as sequential enumeration starting from n. For each number, extract digits and compute the running product while checking divisibility by t. Stop early if the product becomes divisible by t or if a zero digit appears, which guarantees divisibility.

What is the best approach for Smallest Divisible Digit Product I?

Enumeration with early termination is the most practical approach. Start from n and check each number’s digit product, but stop computing the product as soon as it becomes divisible by t or a zero digit appears. This keeps the logic simple while avoiding unnecessary multiplications.

Is Smallest Divisible Digit Product I asked at Google/Amazon/Meta?

The problem itself is from LeetCode and categorized as Easy, focusing on digit manipulation and enumeration. Similar digit-product or digit-processing questions appear in interviews at large tech companies because they test number handling and basic algorithmic reasoning.

What data structure is used in Smallest Divisible Digit Product I?

No complex data structure is required. The solution relies on integer arithmetic, digit extraction using modulo and division, and simple iteration. The problem mainly falls under math and enumeration techniques.

What is the time complexity of Smallest Divisible Digit Product I?

The time complexity is O(k * d), where k is the number of integers checked starting from n and d is the number of digits in each number. Each candidate requires scanning its digits to compute the product. Space complexity is O(1) since only a few variables are used.

Description Hints 2 Solution Video 2:42

3345. Smallest Divisible Digit Product I

Easy73.1% acceptance1 company

You are given two integers n and t. Return the smallest number greater than or equal to n such that the product of its digits is divisible by t.

Example 1:

Input: n = 10, t = 2

Output: 10

Explanation:

The digit product of 10 is 0, which is divisible by 2, making it the smallest number greater than or equal to 10 that satisfies the condition.

Example 2:

Input: n = 15, t = 3

Output: 16

Explanation:

The digit product of 16 is 6, which is divisible by 3, making it the smallest number greater than or equal to 15 that satisfies the condition.

Constraints:

1 <= n <= 100
1 <= t <= 10

Asked at 1 company

Accenture

Topics

Enumeration Math

Hints open one at a time

Hint 1

You have to check at most 10 numbers.

Hint 2

Apply a brute-force approach by checking each possible number.

2:42

Still stuck?Read 3 approaches, or watch a walkthrough.

Open solution