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FleetCode

50. Pow(x, n)

Medium39.0% acceptance22 companies

Implement pow(x, n), which calculates x raised to the power n (i.e., xn).

Example 1:

Input: x = 2.00000, n = 10
Output: 1024.00000

Example 2:

Input: x = 2.10000, n = 3
Output: 9.26100

Example 3:

Input: x = 2.00000, n = -2
Output: 0.25000
Explanation: 2-2 = 1/22 = 1/4 = 0.25

Constraints:

  • -100.0 < x < 100.0
  • -231 <= n <= 231-1
  • n is an integer.
  • Either x is not zero or n > 0.
  • -104 <= xn <= 104
8:10
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1class Solution:
2 def myPow(self, x: float, n: int) -> float:
3
Starter codePython 3Spaces: 4
Examples
Input
2.00000
10
Input
2.10000
3
Input
2.00000
-2
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