Is Mirror Distance of an Integer easy or hard?

Mirror Distance of an Integer is classified as an Easy problem. It mainly tests basic digit manipulation, integer reversal logic, and simple arithmetic operations rather than advanced algorithms or data structures.

Mirror Distance of an Integer Python/Java solution

In Python or Java, iterate through digits to build the reversed number using modulo and division. Maintain a variable for the mirrored value, update it as mirror = mirror * 10 + digit, and finally return Math.abs(original - mirror) or abs(original - mirror).

How to solve Mirror Distance of an Integer in O(n)?

Treat n as the number of digits. Reverse the digits either using string reversal or arithmetic operations. After constructing the mirrored value, return abs(original - mirrored). Since each digit is processed once, the algorithm runs in O(d) time with constant or linear auxiliary space depending on the method used.

What is the best approach for Mirror Distance of an Integer?

The best approach is mathematical digit reversal. Extract digits using modulo (n % 10), build the mirrored number by multiplying the result by 10 and adding the digit, then compute the absolute difference. This runs in O(d) time and O(1) space, where d is the number of digits.

Is Mirror Distance of an Integer asked at Google/Amazon/Meta?

Problems involving digit manipulation and number reversal appear frequently in interviews at large tech companies. While this exact problem may vary, similar tasks that require reversing digits, computing differences, or simulating number transformations are common screening questions.

What data structure is used in Mirror Distance of an Integer?

No complex data structure is required. The optimal solution relies on basic arithmetic operations and integer variables. Some implementations temporarily use strings for convenience when reversing digits.

What is the time complexity of Mirror Distance of an Integer?

The time complexity is O(d), where d is the number of digits in the integer. Each digit is processed exactly once when constructing the mirrored number. Both the string-based and arithmetic approaches have the same time complexity.

Description Hints 1 Solution Video 7:57

3783. Mirror Distance of an Integer

Easy91.5% acceptance2 companies

You are given an integer n.

Define its mirror distance as: abs(n - reverse(n)) where reverse(n) is the integer formed by reversing the digits of n.

Return an integer denoting the mirror distance of n.

abs(x) denotes the absolute value of x.

Example 1:

Input: n = 25

Output: 27

Explanation:

reverse(25) = 52.
Thus, the answer is abs(25 - 52) = 27.

Example 2:

Input: n = 10

Output: 9

Explanation:

reverse(10) = 01 which is 1.
Thus, the answer is abs(10 - 1) = 9.

Example 3:

Input: n = 7

Output: 0

Explanation:

reverse(7) = 7.
Thus, the answer is abs(7 - 7) = 0.

Constraints:

1 <= n <= 10⁹

Asked at 2 companies

Google Bloomberg

Topics

Math

Hints open one at a time

Hint 1

Simulate as described

7:57

Still stuck?Read the written solution, or watch a walkthrough.

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1class Solution:
2    def mirrorDistance(self, n: int) -> int:
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