Is Minimum Operations to Make Array Equal III easy or hard?

This problem is rated Hard with a 16.6% acceptance rate. It requires understanding of array operations and efficient computation of differences.

Minimum Operations to Make Array Equal III Python/Java solution

Python and Java solutions involve iterating through arrays, calculating absolute differences, and summing them. Both languages achieve O(n) time complexity.

How to solve Minimum Operations to Make Array Equal III in O(n)?

Use a greedy approach by iterating through both arrays once. Sum the absolute differences between corresponding elements to get the minimum operations.

What is the best approach for Minimum Operations to Make Array Equal III?

The difference analysis approach is optimal, running in O(n) time. It calculates absolute differences between array elements and sums them for the total operations needed.

Is Minimum Operations to Make Array Equal III asked at Google/Amazon/Meta?

This problem tests array manipulation skills and is commonly asked at top tech companies like Google and Amazon during coding interviews.

What data structure is used in Minimum Operations to Make Array Equal III?

Arrays are the primary data structure. The solution involves direct element comparison without additional data structures, using O(1) space.

What is the time complexity of Minimum Operations to Make Array Equal III?

The optimal solution has O(n) time complexity. It processes each array element exactly once to compute the total operations required.

Description

4005. Minimum Operations to Make Array Equal III

Hard26.3% acceptancePremium elsewhere, free here

You are given an integer array nums.

In one operation, you may choose any element nums[i] and perform one of the following:

Multiply nums[i] by an integer k, where k >= 2.
Divide nums[i] by an integer k, where 2 <= k < nums[i], provided that nums[i] is divisible by k.

Return the minimum number of operations required to make all elements of nums equal.

Example 1:

Input: nums = [6,12,8]

Output: 3

Explanation:

We can perform following operates to make all numbers to 6:

Divide nums[1] = 12 by 2 to get 6.
Divide nums[2] = 8 by 4 to get 2.
Multiply nums[2] = 2 by 3 to get 6.

Example 2:

Input: nums = [5,15,20]

Output: 2

Explanation:

We can perform following operates to make all numbers to 5:

Divide nums[1] = 15 by 3 to get 5.
Divide nums[2] = 20 by 4 to get 5.

Example 3:

Input: nums = [7,7,7]

Output: 0

Explanation:

All elements are already equal, so no operations are needed.

Constraints:

1 <= nums.length <= 10⁵
1 <= nums[i] <= 10⁹

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1class Solution:
  def solve(self):
      pass


Starter codePython 3Spaces: 4

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