Is Minimum Element After Replacement With Digit Sum easy or hard?

Minimum Element After Replacement With Digit Sum is classified as an Easy problem. It focuses on basic array traversal and digit manipulation, making it suitable for beginners practicing math-based transformations and simple linear scans.

Minimum Element After Replacement With Digit Sum Python/Java solution

In Python or Java, iterate through the array, compute the digit sum using repeated modulus (% 10) and division (/ 10), and track the smallest value seen. The implementation is short—usually under 10 lines—and runs in O(n · d) time with constant space.

How to solve Minimum Element After Replacement With Digit Sum in O(n)?

Iterate through the array once and compute the digit sum for each number during traversal. Immediately compare the digit sum with the current minimum and update it if smaller. Because each element is processed once and no extra data structures are used, the solution runs in O(n · d) time and O(1) space.

What is the best approach for Minimum Element After Replacement With Digit Sum?

The best approach is a single-pass traversal of the array. For each number, compute its digit sum using modulus and division, then update the current minimum. This keeps the algorithm O(n · d) time where d is the number of digits, and O(1) extra space.

Is Minimum Element After Replacement With Digit Sum asked at Google/Amazon/Meta?

This exact problem is categorized as an easy array and math problem on LeetCode. Variants involving digit sums, digit manipulation, or array transformations appear in screening rounds across companies like Amazon and Google as warm-up or foundational questions.

What data structure is used in Minimum Element After Replacement With Digit Sum?

The problem primarily uses an array for iteration and simple integer arithmetic for computing digit sums. No additional data structures such as hash maps, stacks, or trees are required. The algorithm relies on basic math operations and a running minimum variable.

What is the time complexity of Minimum Element After Replacement With Digit Sum?

The time complexity is O(n · d). The algorithm processes n numbers, and each digit-sum computation takes up to d operations where d is the number of digits in the integer. Since d is small (≤10 for typical constraints), the runtime behaves close to linear O(n).

3300. Minimum Element After Replacement With Digit Sum - Practice Online

You are given an integer array nums.

You replace each element in nums with the sum of its digits.

Return the minimum element in nums after all replacements.

Example 1:

Input: nums = [10,12,13,14]

Output: 1

Explanation:

nums becomes [1, 3, 4, 5] after all replacements, with minimum element 1.

Example 2:

Input: nums = [1,2,3,4]

Output: 1

Explanation:

nums becomes [1, 2, 3, 4] after all replacements, with minimum element 1.

Example 3:

Input: nums = [999,19,199]

Output: 10

Explanation:

nums becomes [27, 10, 19] after all replacements, with minimum element 10.

Constraints:

1 <= nums.length <= 100
1 <= nums[i] <= 10⁴