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2616. Minimize the Maximum Difference of Pairs

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You are given a 0-indexed integer array nums and an integer p. Find p pairs of indices of nums such that the maximum difference amongst all the pairs is minimized. Also, ensure no index appears more than once amongst the p pairs.

Note that for a pair of elements at the index i and j, the difference of this pair is |nums[i] - nums[j]|, where |x| represents the absolute value of x.

Return the minimum maximum difference among all p pairs. We define the maximum of an empty set to be zero.

Example 1:

Input: nums = [10,1,2,7,1,3], p = 2
Output: 1
Explanation: The first pair is formed from the indices 1 and 4, and the second pair is formed from the indices 2 and 5. 
The maximum difference is max(|nums[1] - nums[4]|, |nums[2] - nums[5]|) = max(0, 1) = 1. Therefore, we return 1.

Example 2:

Input: nums = [4,2,1,2], p = 1
Output: 0
Explanation: Let the indices 1 and 3 form a pair. The difference of that pair is |2 - 2| = 0, which is the minimum we can attain.

Constraints:

  • 1 <= nums.length <= 105
  • 0 <= nums[i] <= 109
  • 0 <= p <= (nums.length)/2

Hints open one at a time

Hint 1
Can we use dynamic programming here?
Hint 2
To minimize the answer, the array should be sorted first.
Hint 3
The recurrence relation is fn(i, x) = min(fn(i+1, x), max(abs(nums[i]-nums[i+1]), fn(i+2, p-1)), and fn(0,p) gives the desired answer.
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1class Solution:
2 def minimizeMax(self, nums: List[int], p: int) -> int:
3
Starter codePython 3Spaces: 4
Examples
Input
[10,1,2,7,1,3]
2
Input
[4,2,1,2]
1
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