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FleetCode

155. Min Stack

Medium58.5% acceptance37 companies

Design a stack that supports push, pop, top, and retrieving the minimum element in constant time.

Implement the MinStack class:

  • MinStack() initializes the stack object.
  • void push(int val) pushes the element val onto the stack.
  • void pop() removes the element on the top of the stack.
  • int top() gets the top element of the stack.
  • int getMin() retrieves the minimum element in the stack.

You must implement a solution with O(1) time complexity for each function.

Example 1:

Input
["MinStack","push","push","push","getMin","pop","top","getMin"]
[[],[-2],[0],[-3],[],[],[],[]]

Output
[null,null,null,null,-3,null,0,-2]

Explanation
MinStack minStack = new MinStack();
minStack.push(-2);
minStack.push(0);
minStack.push(-3);
minStack.getMin(); // return -3
minStack.pop();
minStack.top();    // return 0
minStack.getMin(); // return -2

Constraints:

  • -231 <= val <= 231 - 1
  • Methods pop, top and getMin operations will always be called on non-empty stacks.
  • At most 3 * 104 calls will be made to push, pop, top, and getMin.

Hints open one at a time

Hint 1
Consider each node in the stack having a minimum value. (Credits to @aakarshmadhavan)
8:53
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Open solution
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1class MinStack:
2
3 def __init__(self):
4
5
6 def push(self, val: int) -> None:
7
8
9 def pop(self) -> None:
10
11
12 def top(self) -> int:
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14
15 def getMin(self) -> int:
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17
18
19# Your MinStack object will be instantiated and called as such:
20# obj = MinStack()
21# obj.push(val)
22# obj.pop()
23# param_3 = obj.top()
24# param_4 = obj.getMin()
Starter codePython 3Spaces: 4
Examples
Input
["MinStack","push","push","push","getMin","pop","top","getMin"]
[[],[-2],[0],[-3],[],[],[],[]]
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