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3277. Maximum XOR Score Subarray Queries

Hard43.4% acceptance1 company

You are given an array nums of n integers, and a 2D integer array queries of size q, where queries[i] = [li, ri].

For each query, you must find the maximum XOR score of any subarray of nums[li..ri].

The XOR score of an array a is found by repeatedly applying the following operations on a so that only one element remains, that is the score:

  • Simultaneously replace a[i] with a[i] XOR a[i + 1] for all indices i except the last one.
  • Remove the last element of a.

Return an array answer of size q where answer[i] is the answer to query i.

Example 1:

Input: nums = [2,8,4,32,16,1], queries = [[0,2],[1,4],[0,5]]

Output: [12,60,60]

Explanation:

In the first query, nums[0..2] has 6 subarrays [2], [8], [4], [2, 8], [8, 4], and [2, 8, 4] each with a respective XOR score of 2, 8, 4, 10, 12, and 6. The answer for the query is 12, the largest of all XOR scores.

In the second query, the subarray of nums[1..4] with the largest XOR score is nums[1..4] with a score of 60.

In the third query, the subarray of nums[0..5] with the largest XOR score is nums[1..4] with a score of 60.

Example 2:

Input: nums = [0,7,3,2,8,5,1], queries = [[0,3],[1,5],[2,4],[2,6],[5,6]]

Output: [7,14,11,14,5]

Explanation:

Index nums[li..ri] Maximum XOR Score Subarray Maximum Subarray XOR Score
0 [0, 7, 3, 2] [7] 7
1 [7, 3, 2, 8, 5] [7, 3, 2, 8] 14
2 [3, 2, 8] [3, 2, 8] 11
3 [3, 2, 8, 5, 1] [2, 8, 5, 1] 14
4 [5, 1] [5] 5

Constraints:

  • 1 <= n == nums.length <= 2000
  • 0 <= nums[i] <= 231 - 1
  • 1 <= q == queries.length <= 105
  • queries[i].length == 2
  • queries[i] = [li, ri]
  • 0 <= li <= ri <= n - 1

Asked at 1 company

Hints open one at a time

Hint 1
Precompute the XOR score of every subarray.
Hint 2
Try to find a relationship between XOR score of nums[i..j], nums[i..j + 1], nums[i..j + 2], …. Do you notice any pattern?
Hint 3
If dp[i][j] is the XOR score of subarray nums[i..j], dp[i][j] = dp[i - 1][j] XOR dp[i - 1][j + 1].
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1class Solution:
2 def maximumSubarrayXor(self, nums: List[int], queries: List[List[int]]) -> List[int]:
3
Starter codePython 3Spaces: 4
Examples
Input
[2,8,4,32,16,1]
[[0,2],[1,4],[0,5]]
Input
[0,7,3,2,8,5,1]
[[0,3],[1,5],[2,4],[2,6],[5,6]]
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