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2218. Maximum Value of K Coins From Piles

Hard60.5% acceptance1 company

There are n piles of coins on a table. Each pile consists of a positive number of coins of assorted denominations.

In one move, you can choose any coin on top of any pile, remove it, and add it to your wallet.

Given a list piles, where piles[i] is a list of integers denoting the composition of the ith pile from top to bottom, and a positive integer k, return the maximum total value of coins you can have in your wallet if you choose exactly k coins optimally.

Example 1:

Input: piles = [[1,100,3],[7,8,9]], k = 2
Output: 101
Explanation:
The above diagram shows the different ways we can choose k coins.
The maximum total we can obtain is 101.

Example 2:

Input: piles = [[100],[100],[100],[100],[100],[100],[1,1,1,1,1,1,700]], k = 7
Output: 706
Explanation:
The maximum total can be obtained if we choose all coins from the last pile.

Constraints:

  • n == piles.length
  • 1 <= n <= 1000
  • 1 <= piles[i][j] <= 105
  • 1 <= k <= sum(piles[i].length) <= 2000

Asked at 1 company

Hints open one at a time

Hint 1
For each pile i, what will be the total value of coins we can collect if we choose the first j coins?
Hint 2
How can we use dynamic programming to combine the results from different piles to find the most optimal answer?
18:04
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1class Solution:
2 def maxValueOfCoins(self, piles: List[List[int]], k: int) -> int:
3
Starter codePython 3Spaces: 4
Examples
Input
[[1,100,3],[7,8,9]]
2
Input
[[100],[100],[100],[100],[100],[100],[1,1,1,1,1,1,700]]
7
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