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1589. Maximum Sum Obtained of Any Permutation

Medium41.7% acceptance2 companies

We have an array of integers, nums, and an array of requests where requests[i] = [starti, endi]. The ith request asks for the sum of nums[starti] + nums[starti + 1] + ... + nums[endi - 1] + nums[endi]. Both starti and endi are 0-indexed.

Return the maximum total sum of all requests among all permutations of nums.

Since the answer may be too large, return it modulo 109 + 7.

Example 1:

Input: nums = [1,2,3,4,5], requests = [[1,3],[0,1]]
Output: 19
Explanation: One permutation of nums is [2,1,3,4,5] with the following result: 
requests[0] -> nums[1] + nums[2] + nums[3] = 1 + 3 + 4 = 8
requests[1] -> nums[0] + nums[1] = 2 + 1 = 3
Total sum: 8 + 3 = 11.
A permutation with a higher total sum is [3,5,4,2,1] with the following result:
requests[0] -> nums[1] + nums[2] + nums[3] = 5 + 4 + 2 = 11
requests[1] -> nums[0] + nums[1] = 3 + 5  = 8
Total sum: 11 + 8 = 19, which is the best that you can do.

Example 2:

Input: nums = [1,2,3,4,5,6], requests = [[0,1]]
Output: 11
Explanation: A permutation with the max total sum is [6,5,4,3,2,1] with request sums [11].

Example 3:

Input: nums = [1,2,3,4,5,10], requests = [[0,2],[1,3],[1,1]]
Output: 47
Explanation: A permutation with the max total sum is [4,10,5,3,2,1] with request sums [19,18,10].

Constraints:

  • n == nums.length
  • 1 <= n <= 105
  • 0 <= nums[i] <= 105
  • 1 <= requests.length <= 105
  • requests[i].length == 2
  • 0 <= starti <= endi < n

Asked at 2 companies

Hints open one at a time

Hint 1
Indexes with higher frequencies should be bound with larger values
26:26
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1class Solution:
2 def maxSumRangeQuery(self, nums: List[int], requests: List[List[int]]) -> int:
3
Starter codePython 3Spaces: 4
Examples
Input
[1,2,3,4,5]
[[1,3],[0,1]]
Input
[1,2,3,4,5,6]
[[0,1]]
Input
[1,2,3,4,5,10]
[[0,2],[1,3],[1,1]]
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