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4058. Maximum Pulse Value After One Subarray Rotation

Medium
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4058. Maximum Pulse Value After One Subarray Rotation

Medium37.6% Acceptance

You are given an integer array nums of length n.

Define the pulse value of an integer array arr as the alternating sum starting at index 0: pulse(arr) = arr[0] - arr[1] + arr[2] - arr[3] + ....

You may perform at most one operation on nums:

  • Choose two indices l and r such that 0 <= l < r < n.
  • Left-rotate the subarray nums[l..r] by exactly one position. For example, [a, b, c, d] becomes [b, c, d, a].

Return the maximum pulse value that can be obtained after performing at most one such operation.

Example 1:

Input: nums = [1,5,2]

Output: 6

Explanation:

  • The original pulse value is 1 - 5 + 2 = -2.
  • Rotate the subarray nums[0..1] from [1, 5] to [5, 1].
  • The resulting array is [5, 1, 2] and its pulse value is 5 - 1 + 2 = 6, which is the maximum possible.

Example 2:

Input: nums = [6,4,3]

Output: 7

Explanation:

  • The original pulse value is 6 - 4 + 3 = 5.
  • Rotate the subarray nums[1..2] from [4, 3] to [3, 4].
  • The resulting array is [6, 3, 4] and its pulse value is 6 - 3 + 4 = 7, which is the maximum possible.

Example 3:

Input: nums = [9,7]

Output: 2

Explanation:

The original pulse value is 9 - 7 = 2, which is already maximum. Thus, no rotation is required.

Constraints:

  • 1 <= n == nums.length <= 105
  • -109 <= nums[i] <= 109
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