Is Max Points on a Line easy or hard?

Max Points on a Line is classified as a hard problem because it combines geometry, hashing, and careful edge case handling. Challenges include slope normalization, vertical lines, duplicate points, and avoiding floating‑point precision errors.

Max Points on a Line Python/Java solution

Typical Python and Java solutions iterate through points, compute normalized slopes using GCD to avoid floating point errors, and store counts in a hash map. The maximum slope frequency plus duplicate points determines the number of collinear points.

How to solve Max Points on a Line in O(n)?

Solving the problem in O(n) time is not possible in the general case because determining collinearity requires comparing pairs of points. The best known approach is O(n^2) using slope hashing or line normalization.

What is the best approach for Max Points on a Line?

The most practical approach fixes each point as an anchor and counts slopes to every other point using a hash map. Points with the same normalized slope relative to the anchor lie on the same line. This solution runs in O(n^2) time and O(n) space and is the most common interview implementation.

Is Max Points on a Line asked at Google/Amazon/Meta?

Max Points on a Line appears in interviews at companies that emphasize geometry and hashing techniques, including Google, Amazon, and Meta. It tests slope normalization, hash map usage, and careful handling of duplicates and vertical lines.

What data structure is used in Max Points on a Line?

A hash map is the primary data structure. It stores slope counts for each anchor point or normalized line equations when using the line representation method.

What is the time complexity of Max Points on a Line?

The optimal solution runs in O(n^2) time because each point is compared with every other point to compute slopes. For each anchor point, a hash map tracks slope frequencies in O(n) space.

Description Solution Video 8:14

149. Max Points on a Line

Hard31.6% acceptance16 companies

Given an array of points where points[i] = [x_i, y_i] represents a point on the X-Y plane, return the maximum number of points that lie on the same straight line.

Example 1:

Input: points = [[1,1],[2,2],[3,3]]
Output: 3

Example 2:

Input: points = [[1,1],[3,2],[5,3],[4,1],[2,3],[1,4]]
Output: 4

Constraints:

1 <= points.length <= 300
points[i].length == 2
-10⁴ <= x_i, y_i <= 10⁴
All the points are unique.

Asked at 16 companies

Twitter Waymo LinkedIn Meesho Sprinklr Zoox Apple Citadel

Cisco Zoho NVIDIA

Google

+4 more

Amazon Microsoft Meta Bloomberg

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8:14

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149. Max Points on a Line

Asked at 16 companies

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