There is a number n between 0 and 230 - 1 (both inclusive) that you have to find.
There is a pre-defined API int commonBits(int num) that helps you with your mission. But here is the challenge, every time you call this function, n changes in some way. But keep in mind, that you have to find the initial value of n.
commonBits(int num) acts as follows:
count which is the number of bits where both n and num have the same value in that position of their binary representation.n = n XOR numcount.Return the number n.
Note: In this world, all numbers are between 0 and 230 - 1 (both inclusive), thus for counting common bits, we see only the first 30 bits of those numbers.
Constraints:
0 <= n <= 230 - 10 <= num <= 230 - 1num out of the given range, the output wouldn't be reliable.Loading editor...
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