There is a number n that you have to find.
There is also a pre-defined API int commonSetBits(int num), which returns the number of bits where both n and num are 1 in that position of their binary representation. In other words, it returns the number of set bits in n & num, where & is the bitwise AND operator.
Return the number n.
Example 1:
Input: n = 31
Output: 31
Explanation: It can be proven that it's possible to find 31 using the provided API.
Example 2:
Input: n = 33
Output: 33
Explanation: It can be proven that it's possible to find 33 using the provided API.
Constraints:
1 <= n <= 230 - 10 <= num <= 230 - 1num out of the given range, the output wouldn't be reliable.Loading editor...
31