You are given an integer array nums.
An integer x is called special if:
x appears at least three times in nums.x are equally spaced in nums. In other words, if all occurrences of x are at indices i1 < i2 < ... < im, then i2 - i1 = i3 - i2 = ... = im - im-1.Return the number of distinct special integers in nums.
Example 1:
Input: nums = [1,8,1,5,1,5,8,5]
Output: 2
Explanation:
Therefore, the answer is 2.
Example 2:
Input: nums = [8,8,8,8]
Output: 1
Explanation:
8 is special because it occurs at equally spaced indices 0, 1, 2, and 3. Therefore, the answer is 1.
Example 3:
Input: nums = [8,6,6,8,8]
Output: 0
Explanation:
8 occurs at indices 0, 3, and 4, which are not equally spaced. 6 occurs only twice. Therefore, no integer is special.
Constraints:
3 <= nums.length <= 1051 <= nums[i] <= 109Loading editor...
[1,8,1,5,1,5,8,5]