Is Check Adjacent Digit Differences easy or hard?

Check Adjacent Digit Differences is generally classified as an Easy problem. The logic requires a basic linear scan and simple arithmetic checks between adjacent digits, making it suitable for beginners practicing number manipulation.

Check Adjacent Digit Differences Python/Java solution

The implementation usually iterates through digits and checks abs(digit[i] - digit[i+1]) == 1. Python can iterate over a string or use modulo operations, while Java commonly uses integer division and modulo to extract digits. Both implementations run in O(n) time.

How to solve Check Adjacent Digit Differences in O(n)?

Process digits sequentially and compare every adjacent pair. Extract digits using modulo (num % 10) and integer division (num // 10) or iterate through a string representation. For each pair, check if abs(d1 - d2) equals 1 and stop immediately if the condition fails.

What is the best approach for Check Adjacent Digit Differences?

The best approach is a single linear scan of the digits while checking the absolute difference between adjacent pairs. Extract digits either by converting the number to a string or using modulo and division operations. The optimal implementation runs in O(n) time with O(1) extra space when digits are processed mathematically.

Is Check Adjacent Digit Differences asked at Google/Amazon/Meta?

Problems involving digit manipulation and adjacency checks appear frequently in coding interviews at large tech companies. While this exact problem may vary, similar questions testing number processing, absolute differences, and linear scans show up in screening rounds.

What data structure is used in Check Adjacent Digit Differences?

No complex data structure is required. The solution typically uses simple integer arithmetic or a string representation of the number. The algorithm relies on sequential comparison of digits rather than storing large structures.

What is the time complexity of Check Adjacent Digit Differences?

The time complexity is O(n), where n is the number of digits in the input number. Each digit is processed once while comparing it with its adjacent neighbor. The space complexity can be O(1) with arithmetic extraction or O(n) if the number is converted to a string.

3931. Check Adjacent Digit Differences - Practice Online

You are given a string s consisting of digits.

Return true if the absolute difference between every pair of adjacent digits is at most 2, otherwise return false.

The absolute difference between a and b is defined as abs(a - b).

Example 1:

Input: s = "132"

Output: true

Explanation:

The absolute difference between digits at s[0] and s[1] is abs(1 - 3) = 2.
The absolute difference between digits at s[1] and s[2] is abs(3 - 2) = 1.
Since both differences are at most 2, the answer is true.

Example 2:

Input: s = "129"

Output: false

Explanation:

The absolute difference between digits at s[0] and s[1] is abs(1 - 2) = 1.
The absolute difference between digits at s[1] and s[2] is abs(2 - 9) = 7, which is greater than 2.
Therefore, the answer is false.

Constraints:

2 <= s.length <= 100
s consists only of digits.