Is Bitwise OR of Adjacent Elements easy or hard?

Bitwise OR of Adjacent Elements is categorized as an Easy problem. It mainly checks whether you understand array traversal and the behavior of the bitwise OR operator, making it suitable for beginner-level practice.

Bitwise OR of Adjacent Elements Python/Java solution

The solution in Python or Java uses a simple loop and the | operator. For each index i, compute nums[i] | nums[i+1] and store the value in the result array. The logic is identical across Python, Java, C++, Go, and TypeScript.

How to solve Bitwise OR of Adjacent Elements in O(n)?

Loop through the array from index 0 to n-2. For each position, compute nums[i] | nums[i+1] and append the value to the result array. This single linear pass ensures O(n) time complexity and constant auxiliary space.

What is the best approach for Bitwise OR of Adjacent Elements?

Direct iteration with the bitwise OR operator is the best approach. Traverse the array once and compute nums[i] | nums[i+1] for every index. This produces the result array in O(n) time with O(1) extra space.

Is Bitwise OR of Adjacent Elements asked at Google/Amazon/Meta?

Problems involving bit manipulation and array traversal frequently appear in interviews at companies like Amazon, Google, and Meta. While this exact question may vary, similar tasks testing bitwise operations and linear scans are common in early interview rounds.

What data structure is used in Bitwise OR of Adjacent Elements?

The problem primarily uses a simple array. The algorithm iterates through the input array and builds another array containing the OR result of each adjacent pair. No additional complex data structures are required.

What is the time complexity of Bitwise OR of Adjacent Elements?

The optimal solution runs in O(n) time because each adjacent pair in the array is processed exactly once. Only a single pass through the array is required, and each bitwise OR operation runs in constant time.

3173. Bitwise OR of Adjacent Elements - Practice Online

Given an array nums of length n, return an array answer of length n - 1 such that answer[i] = nums[i] | nums[i + 1] where | is the bitwise OR operation.

Example 1:

Input: nums = [1,3,7,15]

Output: [3,7,15]

Example 2:

Input: nums = [8,4,2]

Output: [12,6]

Example 3:

Input: nums = [5,4,9,11]

Output: [5,13,11]

Constraints:

2 <= nums.length <= 100
0 <= nums[i] <= 100