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This approach involves dividing the number by its prime factors (2, 3, and 5) as long as it is divisible by them. If after removing all these factors, the number reduces to 1, it is an ugly number; otherwise, it is not.
Time Complexity: O(log n).
Space Complexity: O(1).
1function isUgly(n) {
2 if (n <= 0) return false;
3 const primes = [2, 3, 5];
4 for (const p of primes) {
5 while (n % p === 0) {
6 n /= p;
7 }
8 }
9 return n === 1;
10}This JavaScript solution iterates over the prime factors and divides n by each, verifying if n ends up as 1 to classify it as an ugly number.
This alternative approach involves using recursion to systematically divide the number by 2, 3, and 5. By tracing back all divisions reaching 1, this method can also verify the ugliness of a number.
Time Complexity: O(log n).
Space Complexity: O(log n), due to recursion stack.
1#includeThis C function uses recursion to repeatedly divide the number by 2, 3, or 5, checking if the reduced result is 1, confirming the number's ugliness.