Sponsored
Sponsored
To determine whether three segments can form a triangle, we can directly apply the triangle inequality theorem. For segments with lengths x, y, and z to form a triangle, the following conditions must be met:
x + y > zx + z > yy + z > xIf all three conditions are satisfied, then the segments can form a triangle.
Time Complexity: O(1) per triangle check since we only run a constant number of comparisons.
Space Complexity: O(1) since no additional space proportional to input size is used.
1def check_triangle(x, y, z):
2 result = "Yes" if (x + y > z and x + z > y and y + z > x) else "No"
3 print(f"{x} {y} {z} {result}")
4
5triangles = [(13, 15, 30), (10, 20, 15)]
6for sides in triangles:
7 check_triangle(*sides)This Python script defines check_triangle, which prints whether three sides can form a triangle by applying the triangle inequality conditions, iterating over a list of side lengths.
In this approach, we first sort the three sides so that we only need to check one inequality condition instead of three. Given sides x, y, and z, sort them to be a ≤ b ≤ c. Then check: a + b > c.
Sorting reduces the number of comparisons and handles the integer sides efficiently when checking validity of the triangle.
Time Complexity: O(1) since sorting three items is constant time and checking has a constant cost.
Space Complexity: O(1).
class TriangleCheck {
static void CheckTriangle(int x, int y, int z) {
int[] sides = new int[] {x, y, z};
Array.Sort(sides);
string result = (sides[0] + sides[1] > sides[2]) ? "Yes" : "No";
Console.WriteLine($"{x} {y} {z} {result}");
}
static void Main() {
int[][] triangles = new int[][] {new int[] {13, 15, 30}, new int[] {10, 20, 15}};
foreach (var sides in triangles) {
CheckTriangle(sides[0], sides[1], sides[2]);
}
}
}This C# implementation sorts an array of triangle side lengths using Array.Sort, optimizing the checks to just one inequality for determining triangle validity.