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This approach involves sorting the data first and then using a two-pointer technique. By sorting, we can simplify the problem as the elements will be in order. The two-pointer method then efficiently checks possible solutions by limiting the number of checks needed.
Time complexity is O(n log n) due to sorting, and space complexity is O(1).
1function findPair(arr, sum) {
2 arr.sort((a, b) => a - b);
3 let left = 0, right = arr.length - 1;
4
5 while (left < right) {
6 let current_sum = arr[left] + arr[right];
7
8 if (current_sum === sum) {
9 console.log(`Pair found: (${arr[left]}, ${arr[right]})`);
10 return;
11 } else if (current_sum < sum) {
12 left++;
13 } else {
14 right--;
15 }
16 }
17 console.log("No pair found");
18}This JavaScript code performs sorting utilizing Array.sort(). By maneuvering two pointers from respective ends towards the center, it quickly isolates potential pairs whose sum matches the target.
This approach uses a hash table (or dictionary) to keep track of the elements and their complements needed to reach the target sum. By utilizing this lookup, we can reduce the problem to a linear time complexity.
Time complexity is O(n) assuming uniform distribution of hash function (no collisions), and space complexity is O(n).
In this Java implementation, a HashSet stores elements while checking complements efficiently. Each iteration checks if the complement has already been recorded, leading to quick pair identification.