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This approach involves converting each character to its corresponding position in the alphabet and forming a numeric string. We then sum the digits of this number 'k' times to get the resulting integer.
Time Complexity: O(N + kM), where N is the length of the string and M is the number of digits in the transformed number.
Space Complexity: O(M), as we store the transformed number as a string.
The conversion from character position to string number is done using StringBuilder. The integer's digit sum is calculated iteratively k times and updated as a string.
This approach directly calculates the digit sum during the conversion of the string to a number by aggregating the sum of each digit representation, reducing the need for intermediate large integer string handling.
Time Complexity: O(N + k*logM), where M is the intermediate sum value.
Space Complexity: O(1).
1function sumOfDigitsAfterConvert(s, k) {
2 let sum = 0;
3 for (let c of s) {
4 let val = c.charCodeAt(0) - 'a'.charCodeAt(0) + 1;
5 while (val > 0) {
6 sum += val % 10;
7 val = Math.floor(val / 10);
8 }
9 }
10
11 while (--k > 0) {
12 let newSum = 0;
13 while (sum > 0) {
14 newSum += sum % 10;
15 sum = Math.floor(sum / 10);
16 }
17 sum = newSum;
18 }
19
20 return sum;
21}
22
23console.log(sumOfDigitsAfterConvert('zbax', 2));JavaScript makes use of modular arithmetic directly to compute digit sums during conversion with compact loop-based sum calculations, further simplifying the process for k transformations.
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