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After sorting the array, our potential strategy is to focus on bridging the maximum and minimum gap by controlling possible breakpoints where the boundary conditions for minimum and maximum flip due to the presorted state.
Time Complexity: O(n log n) due to the sorting operation. Space Complexity: O(1) if we ignore input space.
1function smallestRangeII(nums, k) {
2 nums.sort((a, b) => a - b);
3 let result = nums[nums.length - 1] - nums[0];
4 for (let i = 0; i < nums.length - 1; i++) {
5 let high = Math.max(nums[i] + k, nums[nums.length - 1] - k);
6 let low = Math.min(nums[0] + k, nums[i + 1] - k);
7 result = Math.min(result, high - low);
8 }
9 return result;
10}
11
12const nums = [1, 3, 6];
13const k = 3;
14console.log(smallestRangeII(nums, k)); // Output: 3This JavaScript function calculates the minimal score by evaluating each possible breakpoint between sorted array elements and dynamically updating the range.
A slight variation that considers minimizing and maximizing simultaneously, with the goal of finding directly altered extremes without sequence traversals.
Time Complexity: O(n log n), Space Complexity: O(1) for array due to in-place.
1function
This JS solution offers extensive analysis by anchoring doubling range increments at both ends of nums to ascertain if middle anomalies can have residual deductions.