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This approach uses a two-pointer technique to shuffle the array. The first pointer starts at the beginning of the array and represents the x values. The second pointer starts at the middle of the array and represents the y values. By iterating over the array and adding elements from these two pointers alternately to a new list, we can achieve the desired shuffle.
Time Complexity: O(n), where n is half the length of the array. We iterate through the array once.
Space Complexity: O(n), for storing the shuffled result.
1function shuffle(nums, n) {
2 let result = [];
3 for (let i = 0; i < n; i++) {
4 result.push(nums[i]);
5 result.push(nums[i + n]);
6 }
7 return result;
8}
9
10let nums = [2, 5, 1, 3, 4, 7];
11let n = 3;
12console.log(shuffle(nums, n));This JavaScript solution initializes an empty array and pushes elements from the two halves of the input array into it alternately to achieve the shuffled order.
An alternate approach is to reorder the array in-place without using additional space. However, given the elements might need to be accessed multiple times, a good understanding of index manipulation and mathematics is required. The complexity to deduce the correct indices for swapping can increase the difficulty.
Time Complexity: O(n^2) in the worst case as the array is shifted multiple times.
Space Complexity: O(1), as the shuffling is done in-place.
1
class Program {
static void ShuffleInPlace(int[] nums, int n) {
for (int i = n; i < 2 * n; i++) {
int y = nums[i];
for (int j = i; j > 2 * (i - n); j--) {
nums[j] = nums[j - 1];
}
nums[2 * (i - n)] = y;
}
}
static void Main() {
int[] nums = {2, 5, 1, 3, 4, 7};
int n = 3;
ShuffleInPlace(nums, n);
Console.WriteLine(string.Join(", ", nums));
}
}In the C# solution, we shuffle the input array in place by assigning elements through systematic index shifts, avoiding extra space use.