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This approach uses a two-pointer technique to shuffle the array. The first pointer starts at the beginning of the array and represents the x values. The second pointer starts at the middle of the array and represents the y values. By iterating over the array and adding elements from these two pointers alternately to a new list, we can achieve the desired shuffle.
Time Complexity: O(n), where n is half the length of the array. We iterate through the array once.
Space Complexity: O(n), for storing the shuffled result.
1import java.util.*;
2
3public class ShuffleArray {
4 public static int[] shuffle(int[] nums, int n) {
5 int[] result = new int[2 * n];
6 for (int i = 0; i < n; i++) {
7 result[2 * i] = nums[i];
8 result[2 * i + 1] = nums[i + n];
9 }
10 return result;
11 }
12 public static void main(String[] args) {
13 int[] nums = {2, 5, 1, 3, 4, 7};
14 int n = 3;
15 int[] result = shuffle(nums, n);
16 System.out.println(Arrays.toString(result));
17 }
18}This Java solution creates a result array of size 2*n and populates it using a loop that alternates between elements from the first half (x values) and the second half (y values) of the input array.
An alternate approach is to reorder the array in-place without using additional space. However, given the elements might need to be accessed multiple times, a good understanding of index manipulation and mathematics is required. The complexity to deduce the correct indices for swapping can increase the difficulty.
Time Complexity: O(n^2) in the worst case as the array is shifted multiple times.
Space Complexity: O(1), as the shuffling is done in-place.
1
This Python example offers an approach to shuffle the array in place by dynamically adjusting each element's position without requiring additional memory.